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ad-work [718]
3 years ago
10

I NEED HELP PLEASE, THANKS! :)

Mathematics
2 answers:
baherus [9]3 years ago
8 0

Answer:

Step-by-step explanation:

Another way of looking at this is

cos\theta=\frac{1}{2}, which is a first quadrant angle where x is positive (it could also be a 4th quadrant angle, and it actually ends up there, but either way we'll get to where we're needing to be). The equation asks us to find the angle theta that has a cos of 1/2. We set up the reference angle in quadrant 1. Since cosine is by definition side adjacent over hypotenuse, we put the value of 1 along the x quadrant since that's the side adjacent to the reference angle, and then put the 2 along the hypotenuse of the right triangle that we form. That means that the side across from the reference angle is the square root of 3 which makes the reference angle a 60 degree angle, or pi/3.

So \theta=\frac{\pi}{3}

Now we need to find the csc of pi/3 - pi/2. Csc is the inverse of the sin ratio, so we can rewrite it in terms of sin:

\frac{1}{sin(\frac{\pi}{3}-\frac{\pi}{2})  } which simplifies to

\frac{1}{sin(-\frac{\pi}{6}) } after finding a common denominator and subtracting.

-\frac{\pi}{6} is a 30 degree angle measured clockwise from the positive axis, putting that 30 degree angle into quadrant 4. On you calculator, you will find that 1 over the sin of -30 degrees is

-2.

Lelu [443]3 years ago
5 0

Answer:  b) -2

<u>Step-by-step explanation:</u>

cos θ = 0.5  

\cos \theta=\dfrac{1}{2}\qquad \rightarrow \qquad \theta =\dfrac{\pi}{3}\\\\\\\csc\bigg(\dfrac{\pi}{3}-\dfrac{\pi}{2}\bigg)\\\\\\=\csc\bigg(-\dfrac{\pi}{3}\bigg)\\\\\\=\csc \bigg(\dfrac{5\pi}{3}\bigg)\\\\\\=\dfrac{1}{\sin (\frac{5\pi}{3})}\\\\\\=\dfrac{1}{-\frac{1}{2}}\\\\\\=\large\boxed{-2}

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On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi
Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0
3 years ago
Two poles, A and B, are 12 meters apart. Pole A is 5 meters high. A rope 20 meters long is tied to the top of pole A and stretch
stepan [7]
The answer should be C, 21. I’ll attach a picture for explanation.
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3 years ago
Angle. How many sides does the polygon have?
tia_tia [17]

The measures of the four angles of quadrilateral ABCD are 36°, 72°, 108° and 144°

<u>Explanation:</u>

A polygon has three or more sides.

Example:

Triangle has 3 sides

Square has 4 sides

Pentagon has 5 sides and so on.

27)

In a quadrilateral ABCD, the measure of ZA, ZB, ZC and ZD are the ratio 1 : 2 : 3 : 4

We know,

sum of all the interior angles of a quadrilateral is 360°

So,

x + 2x + 3x + 4x = 360°

10x = 360°

x = 36°

Thus, the measure of four angles would be:

x = 36°

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4x = 4 X 36° = 144°

Therefore, the measures of the four angles of quadrilateral ABCD are 36°, 72°, 108° and 144°

5 0
3 years ago
Please help and show how u did it im confused please help thanks
VARVARA [1.3K]
#2, Y=8, x=3
because if you subsitute those variables in,
8=3+5
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7 0
3 years ago
Help!!! I need to find the x and y values
gayaneshka [121]

The solution is that x = 26 and y = 9.

In order to find these, we need to note that since the two angles involving x's make a straight line, then they must equal 180 degrees. So we can add them together and set them equal to solve for x.

5x - 17 + 3x - 11 = 180 ----> combine like terms

8x - 28 = 180 ----> add 28 to both sides

8x = 208 -----> divide by 8

x = 26

Now that we have the value of x, we can find the value of the 3x - 11 term. That along with the right angle and the 2y + 5 angle combine to make another straight line. So we can solve by setting that equal to 180 as well.

3x - 11 + 90 + 2y + 5 = 180 ------> Combine like terms

3x + 2y + 84 = 180 -----> Put 26 in for x.

3(26) + 2y + 84 = 180 -----> Multiply

78 + 2y + 84 = 180 ------> Combine like terms again

2y + 162 = 180 ------> Subtract 162 from both sides

2y = 18 -----> Divide by 2

y = 9

6 0
3 years ago
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