Answer:
y = 2x - 5
Step-by-step explanation:
Slope = 2
y-intercept = - 5
Answer:
Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
Exact Form:
x = − 70 ± √4210/30
Decimal Form:
x = −0.03
Step-by-step explanation:
5x(6x+28)=−23
Step 1: Simplify both sides of the equation.
30x2+140x=−23
Step 2: Subtract -23 from both sides.
30x2+140x−(−23)=−23−(−23)
30x2+140x+23=0
Step 3: Use quadratic formula with a=30, b=140, c=23.
x=−b±√b2−4ac/2a
x=−(140)±√(140)2−4(30)(23)/2(30)
x=−140±√16840/60
x=−7/3+1/30√4210 or x=−7/3+−1/30√4210
Answer:
6a) i- 2hrs 36mins ii- 3hrs 12mins
b) car A≈ 76.9km/h car B≈ 62.5km/h
c)------
7a) 35km
b) car A=75km car B=60km
c) 30km
d) car A≈36mins car B≈48mins
Step-by-step explanation:
6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.
b) Using the answer from a, you divide 200km by the time.
For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6
∴ car A: 200/2.6≈ 76.92km/h
For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2
∴ car B: 200/3.2≈ 62.5km/h
7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.
b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).
c) Difference from car A line to car B:
155km-125km=30km
d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.
Hope this helps.
For every c substitute 4 and for every d substitute -2
c=4
d=-2
6c + 5d - 4c - 3d + 3c - 6d
= 6(4)+ 5(-2)- 4(4)- 3(-2)+ 3(4)- 6(-2)
=24+(-10)-16-(-6)+12-(-12)
=24-10-16+6+12+12
=28
Answer:
1) E
2) D
3) G
4) I
Step-by-step explanation:
1)
P = 2(l + w)
P = 2(3a + 3 + 8a - 12)
P = 2(11a - 9)
P = 22a - 18
2)
P = 22a - 18
P = 22(3) - 18
P = 66 - 18
P = 48
3)
P = a + b + c
P = 3b + 7 + 7b - 2 + 7b - 2
P = 17b + 3
4)
P = 17b + 3
P = 17(6) + 3
P = 102 + 3
P = 105
