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love history [14]
3 years ago
7

5x(6x+28)=-23 Help I don't understand

Mathematics
2 answers:
andre [41]3 years ago
4 0
Try using Socratic it’s amazing and soooo good
aksik [14]3 years ago
3 0

Answer:

Solve the equation for  x  by finding  a,  b, and  c  of the quadratic then applying the quadratic formula.


Exact Form:


x  =  −  70  ±  √4210/30


Decimal Form:


x  =  −0.03


Step-by-step explanation:

5x(6x+28)=−23


Step 1: Simplify both sides of the equation.


30x2+140x=−23


Step 2: Subtract -23 from both sides.


30x2+140x−(−23)=−23−(−23)


30x2+140x+23=0


Step 3: Use quadratic formula with a=30, b=140, c=23.


x=−b±√b2−4ac/2a


x=−(140)±√(140)2−4(30)(23)/2(30)


x=−140±√16840/60


x=−7/3+1/30√4210 or x=−7/3+−1/30√4210

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olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

there really isn't anything else to do to simplify the expression
5 0
2 years ago
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Marizza181 [45]

Answer:

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Step-by-step explanation:

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2 years ago
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