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Nadusha1986 [10]
3 years ago
6

Help me ASAP bro this is hella weird

Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0
The answer would be c.
zysi [14]3 years ago
8 0

Answer:

C. 3x^2 + x + 1

Step-by-step explanation:

(3x^2 - 1 + x + 2)

=3x^2 + x + 1

If this helps you, please mark brainliest!

Have a nice day :)

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quinn leaves her house at 10:00 am and runs 3 miles at a steady pace of 6 miles per hour. she relaxes and takes a lunch break fo
Usimov [2.4K]

Answer:

1 hour 45 minutes

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Use technology or a z-score table to answer the question.
Drupady [299]

Answer:

C

Step-by-step explanation:

Finding the z-score:

z = (x - μ) / σ

z = (66 - 57) / 9

z = 1

Using a z-score table or calculator:

P(z < 1) = 0.8413

84.13% of 4000 is:

0.8413 (4000) = 3365.2

Rounding up to the nearest whole number, approximately 3366 students will score less than 66.  Answer C.

8 0
3 years ago
Find the volume of the sphere pictured below. The sphere has a radius of 20 cm. Use 3.14 for pi. Give your answer rounded to the
zhenek [66]

Answer:

33493.3

Step-by-step explanation:

Sphere

Solve for volume

V=4/3πr^3 4/3*3.14*20^3=33493.3

6 0
3 years ago
Sarah is a computer engineer and manager and works for a software company. She receives a
daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = a

Given that:

a_4=129\\a_{10}=207

Formula for n^{th} term of an Arithmetic Progression is given as:

a_n=a+(n-1)d

Where d will represent the number of projects increased every year.

and n is the year number.

a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)

Subtracting (2) from (1):

78 = 6d\\\Rightarrow d =13

By equation (1):

129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90

<em>Number of projects in the first year = 90</em>

<em></em>

<em>b) </em>

Number of projects in the twelfth year =

a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233

Each project pays $500

Earnings in the twelfth year = 233 \times 500 = $116500

Sum of an AP is given as:

S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 \times 1938 = $969000

8 0
2 years ago
Which expression gives the distance between the points
Alla [95]

Answer:

C

Step-by-step explanation:

The formula for finding the distance between 2 points (x1, y1) and (x2, y2) is

d = √[(x2 - x1)² + (y2 - y1)²]

Here (x2, y2) = (2, 3)  and (x1, y1) = (4, -3)

Plugging them gives us

d = √[(2 - 4)² + (3 - (-3))²]

  d = √[(2 - 4)² + (3 + 3)²]

8 0
2 years ago
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