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Irina18 [472]
3 years ago
15

A farm is to be built in the shape of Quadrilateral ABCD, as shown below.

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0
When we have diagonals d_1 and d_2 of a rhombus its area is:

A=\dfrac{1}{2}\cdot d_1\cdot d_2=\dfrac{1}{2}\cdot |AC|\cdot |BD|=\dfrac{1}{2}\cdot12.6\cdot10.4=\dfrac{1}{2}\cdot 131.04=\\\\\\=\boxed{65.52\text{ feet}^2}

Answer C)
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photoshop1234 [79]

To find the value of a variable you must know the basics of pre-Algebra.


Example:


2x+9=39


To find he answer of this you must subtract 9 from both sides

Then you are left with…


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Since 2x=30 means 2 times x equals 30

You can divide 2 from both sides to find the answer

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5 0
3 years ago
Find a rational number and an irrational number that are between 5.2 and 5.5. Include the decimal approximation of the irrationa
maw [93]

Answer:

  • Rational: 5.39
  • Irrational: √29 ≈ 5.39

Step-by-step explanation:

Any number you can write completely that has a value between the given numbers will be a suitable rational number.

There are many ways to find irrational numbers in the given range. You can make one up, such as ...

... 5.3102003000400005000006...

a non-terminating, non-repeating decimal. (This one has a pattern that makes it easy to extend, but that doesn't make it rational.)

Or, you can use roots, logs, trig functions, exponential functions, or any of the other functions we study that have irrational values. You can add, subtract, or combine them in other ways. (tan(70°)+∛20, for example) For this, I chose √29, because that square root is between the given numbers and 29 is not a perfect square.

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3 years ago
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lyudmila [28]
Yes you can get help.
7 0
3 years ago
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List the integers that satisfy both these inequalities.<br> Put the answers on one line.
bekas [8.4K]

Answer:

-7, -6, -5, -4, -3

Step-by-step explanation:

Given:

2x + 5 < 0

x > -8

Thus, we can combine both statements to find out integers that satisfy both inequalities.

2x + 5 < 0

Let's find x

2x < 0 - 5 (substraction property)

2x < -5

Divide both sides by 2

x < -5/2

This implies that -5/2 is greater than the set of values of x.

The second inequality, x > -8 implies that -8 is less than the value of x.

Les combine both:

-8 < x < -5/2

Therefore, the possible set of integers are whole numbers between the range of -8 and -5/2 which excludes -8 and -5/2.

Thus, they are:

-7, -6, -5, -4, -3

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3 years ago
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Harrizon [31]
The answer to the question

7 0
3 years ago
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