Let D be dogs and C be cats
<em>dogs, d, is initially five less than twice the number of cats, c</em>
D + 5 = 2C
<em>If she decides to add three more of each, the ratio of cats to dogs will be</em>
D + 8 = 2C + 3
<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>
Simply plug in the numbers
20 + 5 = 2(15)
This is clearly not true: 25 does not equal 30
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Choice a.....................
Answer:
One
Explanation:
3
y
=
18
x
+
21
XXX
⇔
y
=
6
x
+
7
5
y
+
55
=
30
x
XXX
⇔
y
=
6
x
−
11
both equations are linear and they are not co-linear
therefore there is exactly 1 solutio
11/2x=2
2/11(11/2)x=2(2/11)
x=4/11