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Arada [10]
2 years ago
9

Why are communities that are more diverse usually more stable?

Biology
1 answer:
serg [7]2 years ago
7 0
<span>It is going to depend on what you consider stable. A diverse population would be more resistant to disease because of simple biology. The more sources for possible resistance the better the heterogeneous pool will be at resisting disease. You also have to take in to consideration things like the availability of modern medicine and the ability to be isolated during illness. </span><span> Personally I think it has to do with the fact that many of the worlds more diverse population centers are also many of the worlds largest population centers which make them less prone to invasion on that basis alone. </span>


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In guinea pigs hair straightness or curliness is thought to be governed by a single pair of alleles showing incomplete dominance
Nimfa-mama [501]

Answer:

Frequency of allele S is p = 0.4939

Frequency of allele C is q = 0.666

The population is not in Hardy-Weinberg equilibrium

Explanation:

Given -

Number of individuals with straight hair = 244

Number of individuals with curly hair = 444

Number of individuals with Wavy hair = 312

Let "p" represents the frequency for allele for straight hair and "q" represents the frequency for allele for curly hair

p^2 represents the frequency of genotype "SS"

p^{2} = \frac{244}{1000} \\= 0.244

q^2 represents the frequency of genotype "CC"

p^{2} = \frac{444}{1000} \\= 0.444

2pq represents the frequency of genotype "SC"

2pq = \frac{312}{1000} \\= 0.312

Frequency of allele S is p

= \sqrt{0.244} \\= 0.4939

Frequency of allele C is q

tex]= \sqrt{0.444} \\= 0.666[/tex]

For being in Hardy Weinberg's equation-

p+q=1\\

Substituting the values in above equation, we get -

0.4939+0.666\neq 1

hence, the population is not in Hardy-Weinberg equilibrium

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tube c

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<h2>It may become endangered </h2>

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