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3 years ago

What is 2 times 3/5 + 1/5

Mathematics

2 answers:

lubasha [3.4K]3 years ago

5 0

The answer would be 1.4

sertanlavr [38]3 years ago

5 0

1.4th is your answer....hopefully i helped if i did the best plzz give brainliest answer (trust me i need it) and have a great day!!

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A bucket contains 11 2/3 gallons of water and 5/6 is full. How many gallons of water would be in a full bucket? Write a multipli

vagabundo [1.1K]

Answer:

14 gallons

Step-by-step explanation:

If 11 2/3 gallons represents 5/6 full bucket then we can equate that

x=1 full

$x=\frac {11 2/3}{5/6}=14$

Therefore, the bucket requires 14 gallons

7 0

3 years ago

Read 2 more answers

A backyard is 40.5 feet long and 25 feet wide. In order to install a pool, the yard needs to be reduced by a scale of 1/3. What

cestrela7 [59]

Answer:The area of the reduced backyard is 112.5 square feet

Step-by-step explanation:

The initial length of the backyard is 40.5 feet long.

The initial width of the backyard is 25 feet wide.

In order to install a pool, the yard needs to be reduced by a scale of 1/3. This means that the new length of the backyard is would be

40.5 × 1/3 = 40.5/3 feet lonng

The new width of the backyard would be

25 × 1/3 = 25/3 feet wide

The backyard is rectangular in shape. Area of a rectangle is length × width. The area of the reduced backyard becomes

40.5/3 × 25/3 = 1012.5/9 = 112.5 square feet

8 0

4 years ago

Read 2 more answers

PLEASE HELP ME 11 points

AysviL [449]

3r<= 4r - 6
4r - 6 >= 3r
r >= 6

solutions r >= 6

answer
6
7

5 0

4 years ago

HELP ME PLEASEE

VLD [36.1K]

im 89% positive that no is the correct answer

Step-by-step explanation:

9.6*3.1= 29.76

11.1*2.8=-31.08

-----------------------

1.32-3= 1.68

3 0

3 years ago

The maintenance department at the main campus of a large state university receives daily requests to replace fluorecent lightbul

pshichka [43]

Answer:

P₂ [ 32 ≤ X ≤ 46 ] = 47,71 %

Step-by-step explanation:

The rule:

68-95-99.7

establishes

P₁ [ μ₀ - σ ≤ X ≤ μ₀ + σ] ≈ 0,683

P₂ [ μ₀ - 2σ ≤ X ≤ μ₀ + 2σ] ≈ 0,954

P₃ [ μ₀ - 3σ ≤ X ≤ μ₀ + 3σ] ≈ 0,997

For our paticular case we have

μ₀ = 46

σ = 7

Then we get:

μ₀ - σ = 39 μ₀ + σ = 53

μ₀ - 2σ = 32 μ₀ + 2σ = 60

μ₀ - 3σ = 25 μ₀ + 3σ = 67

We were asked by % of replacement request numbering between 32 and 46.

Normal curve is symmetric therefore μ₀ - 2σ = 32 is just half of the interval P₂ [ μ₀ - 2σ ≤ X ≤ μ₀ + 2σ] ≈ 0,954, then between 32 and 46 the porcentage of lightbulb is 0,954/2 , is 0,4771 or 47,71 %

P₂ [ μ₀ - 2σ ≤ X ≤ μ₀ ] = P₂ [ 32 ≤ X ≤ 46 ] = 47,71 %

6 0

4 years ago