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Mathematics

1 answer:

VLD [36.1K]3 years ago

3 0

im 89% positive that no is the correct answer

Step-by-step explanation:

9.6*3.1= 29.76

11.1*2.8=-31.08

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1.32-3= 1.68

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Please take a look at the picture. Please write your answer with an explanation.

Ahat [919]

Step-by-step explanation:

what answer is needed ? the result of the calculation ?

I assume this is the case.

remember that regarding the sequence of operations brackets are first, then exponents, then "dot" operations (× and ÷), and only at the very least come the "dash" operations (+ and -).

and that a combination of - + or + - results in -.

14 + 16 ÷ 2³ - (12 + 3²) ÷ 7 + 2 × (-5) =

14 + 16 ÷ 2³ - (12 + 9) ÷ 7 - 2 × 5 =

14 + 16 ÷ 2³ - 21 ÷ 7 - 2 × 5 =

14 + 16 ÷ 8 - 21 ÷ 7 - 2 × 5 =

14 + 2 - 3 - 10 = 3

7 0

2 years ago

On Monday, Anya read 11 pages of a book in 1/2 hour. On Tuesday, she read 18 pages in 3/4 hour. Did Anya's reading speed increas

Lerok [7]

The way you should go about solving this really depends on how your teacher taught you...However, here's what I would recommend...
You know that 1/2 an hour is equal to 30 minutes, and 3/4 of an hour is equal to 45 minutes.
Using this you can then solve for how many pages she read per minute by dividing the number of pages read by the number of minutes read:11 pages/ 30 minutes to give you Monday's reading speed,and18 pages/ 45 minutes to give you Tuesday's reading speed.

Next, to calculate a percentage increase you need to do the following:
1. Determine the difference between the speeds (this means you will subtract Monday's reading speed from Tuesday's reading speed.)
2. Next you take that number and divide it by Monday's reading speed.
3. Multiply that answer by 100 to get the percentage.

I'm not going to tell you the speeds, as you should try to attempt to solve it by yourself, and I'm sure you need to show your work. I will however tell you that you should find there was a 3.3% increase from Monday to Tuesday.

If you need more help, let me know!

4 0

3 years ago

18. Determine the common difference, the fifth term, and the sum of the first 100 terms of the following sequence:

Ksenya-84 [330]

$a_1=1,\ a_2=2.5,\ a_3=4,\ a_4=5.5,\ ...\\\\a_2-a_1=2.5-1=1.5\\a_3-a_2=4-2.5=1.5\\a_4-a_3=5.5-4=1.5\\a_{n+1}-a_n=1.5=constans\\\\\text{It's an arithmetic sequence with}\\a_1=1,\ \boxed{d=1.5}\\\\a_n=a_1+(n-1)d\to a_n=1+(n-1)(1.5)=1+1.5n-1.5\\\\a_n=1.5n-0.5\\\\a_5=1.5(5)-0.5=7.5-0.5=7\\\boxed{a_5=7}\\\\\text{The formula of a Sum of the First n Terms of an Arithmetric Sequence:}\\\\S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n\\\\\text{We have:}\\a_1=1,\ d=1.5,\ n=100\\\\\text{Substitute}$

$S_{100}=\dfrac{(2)(1)+(100-1)(1.5)}{2}\cdot100=\dfrac{2+(99)(1.5)}{1}\cdot50\\\\=(2+148.5)\cdot50=150.5\cdot50=7,525\\\\\boxed{S_{100}=7,525}\\\\Answer:\\the\ common\ difference:\ d=1.5\\the\ fifth\ term:\ a_5=7\\the\ sum\ of\ first\ 100\ terms:\ S_{100}=7,525$