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Dovator [93]
3 years ago
5

the coordinates of a line segment are (1,6) and (11, -4). what is the length of the line segment? round your answer to the neare

st tenth. a. 7.1 b. 14.1 c. 50 d. 200
Mathematics
1 answer:
ddd [48]3 years ago
3 0
The length of the line segment AB where A(x_A;\ y_A) and B(x_B;\ y_B)

|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

We have: A(1;\ 6);\ B(11;-4)

subtitute

|AB|=\sqrt{(1-11)^2+(6-(-4))^2}=\sqrt{(-10)^2+10^2}=\sqrt{100+100}\\\\=\sqrt{100\cdot2}=\sqrt{100}\cdot\sqrt2=10\sqrt2\approx14.1

Answer: b. 14.1
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coin $a$ is flipped three times and coin $b$ is flipped four times. what is the probability that the number of heads obtained fr
ivolga24 [154]

The probability that the number of heads obtained from flipping the two fair coins is the same is 35/128.

Probability:

Probability means the fraction of favorable outcome and the total number of outcomes.

So it can be written as,

Probability = Favorable outcomes / Total outcomes

Given,

The coin a is flipped three times and coin b is flipped four times.

Here we need to find the probability that the number of heads obtained from flipping the two fair coins is the same.

We know that,

There are 4 ways that the same number of heads will be obtained;

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The probability of both getting 0 heads is

$\left(\frac12\right)^3{3\choose0}\left(\frac12\right)^4{4\choose0}=\frac1{128}$

Probability of getting 1 head,

$\left(\frac12\right)^3{3\choose1}\left(\frac12\right)^4{4\choose1}=\frac{12}{128}$

Probability of getting 2 heads is,

$\left(\frac12\right)^3{3\choose2}\left(\frac12\right)^4{4\choose2}=\frac{18}{128}$

And the probability of getting 3 heads is,

$\left(\frac12\right)^3{3\choose3}\left(\frac12\right)^4{4\choose3}=\frac{4}{128}$

Therefore, the probability that the number of heads obtained from flipping the two fair coins is the same is,

=> (1/128) + (12/128) + (18/128) + (4/128)

=> 35/128.

To know more about probability here

brainly.com/question/14210034

#SPJ4

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