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Schach [20]
3 years ago
14

Make x the subject: 1. ax + 2d = 2cx + 5b

Mathematics
2 answers:
malfutka [58]3 years ago
6 0
Download photomath it solves and shows the steps
ra1l [238]3 years ago
5 0

Answer:

x = \frac{5b-2d}{a-2c}

Step-by-step explanation:

Given

ax + 2d = 2cx + 5b (subtract 2d from both sides )

ax = 2cx + 5b - 2d ( subtract 2cx from both sides )

ax - 2cx = 5b - 2d ← factor out x from each term on the left side

x(a - 2c) = 5b - 2d ← divide both sides by (a - 2c)

x = \frac{5b-2d}{a-2c}

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1/6 + 1/2 equals show steps
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1/2=3/6

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3 0
3 years ago
Write the slope-intercept equation of the line parallel to 5y = 2x + 20 that goes through (-1, 3).
poizon [28]

The first thing I'll do is solve "5y = 2x + 20" for "<span>y=</span>", so that I can find my reference slope:

y = (2/5)x + 4;

So the reference slope from the reference line is <span>m = 2/5;</span>.

Now I need to find two new slopes, and use them with the point they've given me; namely, with the point (-1, 3). They want me to find the line through (4, –1) that is parallel to 5y = 2x + 20; that is, through the given point, they want me to find a line that has the same slope as the reference line. 

Since a parallel line has an identical slope, then the parallel line through (-1, 3) will have slope <span>m = 2/5</span>. Now I have a point and a slope! So I'll use the point-slope form to find the line: y - 3 = (2/5)( x + 1);

Finally, y = (2/5)x + 17/5;


3 0
3 years ago
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Andre45 [30]

Answer:

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4 0
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