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igomit [66]
3 years ago
10

HELLPPPPP!!!! AND THANK YOUU​

Mathematics
2 answers:
Anni [7]3 years ago
7 0
The answer is E. if i were you, i would just plug it into my calculator
Snezhnost [94]3 years ago
5 0

Answer:

I'm probably wrong, but I think it's A. I don't use the same school website as you do, so I can't tell if it's a multiple choice. Sorry if it is and I'm wrong though!

<em />

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What is the last term?<br>A. 4X2<br>B. -16<br>C. 16<br>D. -4X2​
sleet_krkn [62]

Answer:

c.16

Step-by-step explanation:

hjdjfjnfmforoeofmg

3 0
3 years ago
Corinne has a job selling magazines. She earns $7.50 per hour plus 20% of the total amount of her sales. She also gets an allowa
Lynna [10]
Part A:  Coefficient:  either 7.50 or 0.20
Part B:

7.50 (25) + 0.20 (300) + 40
187.50 + 60 + 40 = $287.50

Part C: After her raise, the first term will change from 7.50h to 9h
4 0
3 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 10 altimeters that are correctly calibrated and two that ar
mart [117]

Answer:  a) 0.545,b) 0.41, c) 0.045, d) not possible.

Step-by-step explanation:

The Sky Ranch is a supplier of aircraft parts. Included in stock are 10 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected without replacement. Let the random variable

x represent the number that are not correctly calibrated.

Complete the probability distribution table.

x={0,1,2,3}

P(x=0)=?

P(x=1)=?

P(x=2)=?

P(x=3)=?

Since we have given that

n = 12

number of good one = 3 from 10

number of bad one = 2

So, P(X=0)=\dfrac{^{10}C_3\times ^2C_0}{^{12}C_3}=\dfrac{120}{220}=0.545

P(X=1) = \dfrac{^{10}C_2\times ^2C_1}{^{12}C_3}=\dfrac{90}{220}=0.41

P(X=2)=\dfrac{^{10}C_1\times ^2C_2}{^{12}C_3}=\dfrac{10}{220}=0.045

P(X=3) is not possible.

Hence, a) 0.545,b) 0.41, c) 0.045, d) not possible.

5 0
3 years ago
⚠️WILL GIVE BRAINLIEST!!!
sergeinik [125]

Answer: 42 Units Cubed

Step-by-step explanation:

Volume of a Prism is typically length * width * height

in the problem the 5 and 1/4 is the area of that base so it is is the height and width already multiplied

so now just multiply the length, which is 8, to the area of the base to find the volume

8*5\frac{1}{4} \\8*\frac{21}{4} \\2*21\\42

5 0
3 years ago
Read 2 more answers
Could a polyhedron exist with the given number of faces, vertices, and edges? Drag yes or no to each combination
DanielleElmas [232]

Answer:

(a) No

(b) No

(c) No

Step-by-step explanation:

Given

See attachment

Required

Select Yes or No for each

To do this, we make use of Euler's formula

F + V - E = 2

Where

F \to Faces; V \to Vertices; E \to Edges

(a):\ Faces = 8; Vertices = 12; Edges = 6

Using: F + V - E = 2

8 + 12 - 6 = 2

14 = 2

<em>The above equality is false. Hence, (a) does not exist</em>

(b):\ Faces = 6; Vertices = 6; Edges = 4

Using: F + V - E = 2

6 + 6 - 4 = 2

8 = 2

<em>The above equality is false. Hence, (b) does not exist</em>

<em />

<em />(c):\ Faces = 20; Vertices = 30; Edges = 12<em />

Using: F + V - E = 2

20 + 30 - 12 = 2

38 = 2

<em>The above equality is false. Hence, (c) does not exist</em>

5 0
3 years ago
Read 2 more answers
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