Answer:
B
Step-by-step explanation:
Both of them have the same variable and are both raised to the 5th power (Like the example in the last sentence of the text)
The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.
If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.
The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.
The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ = coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.
This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.
Answer:
Step-by-step explanation:
given that diameter of the pipe = 14 inches
radius = 7 inches
Length =2156 inches
Pipe is in the form of a cylinder
Volume of cylinder = pi r^2 h
where r = radius and h = l = 2156
We have to substitute the values of r and h.
Let us take pi as 22/7
= 22/7 (7)(7)(2156)
Cancel out 7 and multiply the remaining 22 ,7 and 2156
=332024 cubic inches
The 2nd one is the right one.!