Answer:
So no single branch would have too much power.
Answer: D) Segmental level, projection level, precommand level
Explanation: The hierarchical organisation of the motor control system is only one aspect, besides it there is a parallel one. The motor control system is responsible for regulating movement and as such is crucial for the body's motility, which includes directional movement and reflexes. Of course, motor control only exists in organisms that have a nervous system.
As for the hierarchy of the motor control system, the lowest in the hierarchy is the segmental level. It consists of reflexes and parts of the nervous system in charge of automatic movements.
Second in the hierarchy from the lowest to the highest is the projection level and helps in the functioning of the segmental level, i.e, for the regulation of reflexes and for monitoring the multi neuronal system.
The highest level is the precommand level, which is responsible for controlling the output impulses that control the finest, most precise movements of the body, responsible for starting and stopping movements, regulating the muscles, and preventing unwanted movements.
Answer:
i think it is depression she needs somebody to talk to :D
Explanation:
Answer:

Explanation:
Your question has one part only: <em>a) The average weight of the eggs produced by the young hens is 50.1 grams, and only 25% of their eggs exceed the desired minimum weight. If a Normal model is appropriate, what would the standard deviation of the egg weights be?</em>
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<h2><em>Solution</em></h2><h2><em /></h2>
You are given the <em>mean</em>, the reference value, and the <em>percent of egss that exceeds that minimum</em>.
In terms of the parameters of a normal distribution that is:
- <em>mean</em> =<em> 50.1g</em> (μ)
- Area of the graph above X = 51 g = <em>25%</em>
Using a standard<em> normal distribution</em> table, you can find the Z-score for which the area under the curve is greater than 25%, i.e. 0.25
The tables with two decimals for the Z-score show probability 0.2514 for Z-score of 0.67 and probabilidad 0.2483 for Z-score = 0.68.
Thus, you must interpolate. Since, (0.2514 + 0.2483)/2 ≈ 0.25, your Z-score is in the middle.
That is, Z-score = (0.67 + 0.68)/2 = 0.675.
Now use the formula for Z-score and solve for the <em>standard deviation</em> (σ):


