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3 years ago

What is the true solution to ln20+ln5=2lnxA)x=5B)x=10C)x=50D)x=100

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

6 0

The answer is C. Hope this helps!

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Question 9 of 25

tresset_1 [31]

Answer:

One approach to this problem is to obtain the graph for the given equation.

We need to find every intersection those functions have with the axis 'x' and 'y'

starting with g(x)

g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis

g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis

Lets do the same for f(x)

g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis

We dont need to find any other, since always y=x

By plotting we have the attached picture

Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Suppose that a teacher plans to give four students a quiz. The minimum possible score on the quiz is 0, and the maximum possible

denis23 [38]

Answer:

5 is the largest it could possibly be

8 0

3 years ago

Please help me!!!!with this!!!

kodGreya [7K]

5x+9-3x=11

5x-3x=11-9

2x=2

2:2

x=1

8 0

3 years ago

If f(x)=4^x, find f(4)

lina2011 [118]

Answer:

$\huge\boxed{f(4) = 256}$

Step-by-step explanation:

Given function is:

$f(x) = 4^x$

Put x = 4

So,

$f(4) = 4^4\\\\f(4) = 256\\\\\rule[225]{225}{2}$

Hope this helped!

6 0

2 years ago

Determine the equations of the vertical and horizontal asymptotes if any for f(x)=x/x-5

Gelneren [198K]

Answer:

Horizontal Asymptote: x = 0

Vertical Asymptote: x = 5

Step-by-step explanation:

The function is given as $f(x)=\frac{x}{x-5}$

Horizontal asymptotes are found by equating numerator to 0 and solving for x

Vertical asymptotes are found by equating denominator to 0 and solving for x

Horizontal Asymptote:

x = 0

Vertical Asymptote:

x - 5 = 0

x = 5

5 0

3 years ago