What is the true solution to ln20+ln5=2lnx A)x=5 B)x=10 C)x=50 D)x=100

I need help pleaseee

kumpel [21]

Answer: $7448

Step-by-step explanation:

Year 1: 1.218x

Year 2: 1.218(1.218x)

Year 3: 1.218(1.218(1.218x))

Year 4: 1.218(1.218(1.218(1.218x)))

Year 5: 1.218(1.218(1.218(1.218(1.218x))))

Year 6: 1.218(1.218(1.218(1.218(1.218(1.218x)))))

Year 7: 1.218(1.218(1.218(1.218(1.218(1.218(1.218x))))))

Year 8: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x)))))))

Year 9: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x))))))))

Year 10: 1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218(1.218x)))))))))

Year 11: x(1.218¹¹)

Year 12: x(1.218¹²) = 79,400

x(10.6602517) = 79,400

x = 79,400/10.6602517

x=7448.22939

x = $7448

Hope this helps!

6 0

1 year ago

I need help lolsssss

MissTica

Answer:

$0.75 per song

Step-by-step explanation:

Given that the relationship between variable s and c is a proportional relationship, and is represented by the equation, c = 0.75s.

Where,

c = total costs

s = number of songs

The constant of proportionality, k, = 0.75.

Thus, 0.75 represents the cost per sing downloaded.

The answer is:

✔️$0.75 per song

7 0

2 years ago

Help ples me i hate ixl

DiKsa [7]

ANSWER:

As we know that,

Volume of triangular prism = 1/2Bh

1/2 × (5)² × 8

1/2 × 25 × 8

100cm³.

3 0

2 years ago

Read 2 more answers

In a survey of 603 adults, 98 said that they regularly lie to people conducting surveys. Create a 99% confidence interval for th

marysya [2.9K]

Answer:

The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).

Step-by-step explanation:

The formula for estimating the population proportion by a confidence interval is given by:

$\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}$

Where:

$\hat{p}$ is the sample's proportion of success, which in this case is the people that regularly lie during surveys,

$z_{\alpha /2}$ is the critical value needed to find the tails of distribution related to the confidence level,

$n$ is the sample's size.

First we compute the $\hat{p}$ value:

$\hat{p}=\frac{successes}{n}=\frac{98}{603}=0.1625$

Next we find the z-score at any z-distribution table or app (in this case i've used StatKey):

$z_{\alpha /2}=2.576$

Now we can replace in the formula with the obtained values to compute the confidence interval:

$\hat{p}\pm z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}=0.1625\pm 2.576\times\sqrt{\frac{0.1625\times(1-0.1625)}{603}}=(0.1238, 0.2012)$

5 0

2 years ago

UnansweredIf Measure of angle a is 155°, what is Measure of angle c?

Gnom [1K]

Answer: 155°

because ∠a and ∠c are 2 opposing angles => m∠a = m∠c = 155°

Step-by-step explanation:

8 0

2 years ago

What is the true solution to ln20+ln5=2lnxA)x=5B)x=10C)x=50D)x=100