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Andre45 [30]
3 years ago
13

5.

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0

Answer:

i am not so sure but I think its 10x = 33

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Two negative integers have a sum of -12 and a
emmainna [20.7K]

Answer:

The two integers are -1 and -11

Step-by-step explanation:

If you add -1 to -11, you would apply the rule of adding negatives (add then put the sign of the larger number). 11+1=12. They are both negative, so it would then become -12. -1 X -11=11 because when multiplying negatives, two of the same sign are positive

7 0
3 years ago
Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

8 0
3 years ago
Read 2 more answers
Can the mean (average) be greater than the largest number in a data set?
salantis [7]
No it can never be greater than the largest number in the set because an average (or a mean) is the "<span> number expressing the central or typical value in a set of data, in particular the mode, median, or (most commonly) the mean, which is calculated by dividing the sum of the values in the set by their number." c:</span>
3 0
3 years ago
Explain why the quadratic relation y=2x^2+3x+5 would have no zeros
alex41 [277]

Complete the square to rewrite the quadratic:

2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5

... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5

... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8

... = 2 (<em>x</em> + 3/4)² + 31/8

Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.

5 0
3 years ago
Please help me I don't understand. Can someone go step by step explaining what I need to do
DiKsa [7]
For a you need to do (10 times 13) plus (10 times 7) because there's two boxes one is shaded.

For b you need to do (7.5 times 20) plus (2.5 times 20)
8 0
3 years ago
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