All categories

3 years ago

Identify m∠C in the triangle shown. (ASAP PLS HELP!)

Mathematics

2 answers:

IrinaVladis [17]3 years ago

4 0

C. 88 + 71 = 159. 180 - 159 = 21

dlinn [17]3 years ago

3 0

Answer:

$x = 21$

Step-by-step explanation:

Apply triangle interior theorem,

$71 + 88 + x = 180$

$159 + x = 180$

$x = 21$

You might be interested in

WILL GIVE 100 POINTS PLS HELP RN EVEN IF ITS JUST A FEW

Sophie [7]

1. 20,000×10%=2,000

2. 20,000×14%=2,800

3. 20,000×5%=1,000

4. Business Marketing

5. 20,000×30%=6,000

5 0

2 years ago

Solve for S 12s = 72

ryzh [129]

Answer:

s=6

Step-by-step explanation:

72/12=6 simplify both sides

3 0

3 years ago

Read 2 more answers

Identify the interval on which the quadratic function is positive.

Alenkasestr [34]

Answer:

$\textsf{1. \quad Solution: $1 < x < 4$,\quad Interval notation: $(1, 4)$}$

$\textsf{2. \quad Solution: $-2 < x < 4$,\quad Interval notation: $(-2, 4)$}$

Step-by-step explanation:

<h3>Question 1</h3>

The intervals on which a quadratic function is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a negative leading coefficient, the parabola opens downwards. Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x-1=0 \implies x=1$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is positive is:

Solution: 1 < x < 4
Interval notation: (1, 4)

<h3>Question 2</h3>

The intervals on which a quadratic function is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a positive leading coefficient, the parabola opens upwards. Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x+2=0 \implies x=-2$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is negative is:

Solution: -2 < x < 4
Interval notation: (-2, 4)

3 0

1 year ago

The longest side of a triangle is 5 inches. Longer than the shortest side. The medium side is 4 inches. Longer than the shortest

Llana [10]

Answer:

The answer to your question is L = 10 in , M = 9 in ; S = 5 in

Step-by-step explanation:

Data

longest side = 5 + x in

medium side = 4 + x in

shortest side = x

Perimeter = 24 in

Process

1.- Write and equation to solve this problem

Perimeter = longest side + medium side + shortest side

Substitution

24 = (5 + x) + (4 + x) + x

Simplification

24 = 5 + x + 4 + x + x

24 = 9 + 3x

24 - 9 = 3x

15 = 3x

x = 15/3

x = 5

2.- Calculate the lengths of the side

Longest side = 5 + 5 = 10 in

Medium side = 5 + 4 = 9 in

Shortest side = 5 in

6 0

3 years ago

Read 2 more answers

Can you please help me....Thank you!

PIT_PIT [208]

Answer:

mean=7

median=8

range=9

mode=3

mean=15

mode=17

range=14

median=14

mean=11

mode=none

range=10

median=4.5

mean=6

mode=4

range=13

median=4

Step-by-step explanation:

there you go, I think that's right but it's been awhile since I've had to do mode mean median and range

4 0

2 years ago