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mina [271]
3 years ago
8

Please help! Due tonight!

Mathematics
1 answer:
Kay [80]3 years ago
3 0

Answer:

B. 6,8,10

Step-by-step explanation:

to find a right triangle the equation: a^2 + b^2 = c^2, so just plug each number in to see.

6^2 + 8^2 = !0^2

36 + 64 = 100

100 = 100

Personally i knew almost immediately because 3,4,5 are the most common right triangles example and 6,8,10 are just a x2 of them so yea.

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WARRIOR [948]

Answer:

The range of values likely to contain the true value of the population parameter is between 44% and 52%.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

These bounds are dependent of the sample mean and of the margin of error.

The lower bound is the sample mean subtracted by the margin of error, while the upper bound is the margin of error added to the sample mean.

The confidence interval is likely to contain the true value of the population parameter.

In this question:

Sample mean: 48%

Margin of error: 4%

48 - 4 = 44%

48 + 4 = 52%

The range of values likely to contain the true value of the population parameter is between 44% and 52%.

7 0
3 years ago
PLEASE HELP IN ONE MINUTE
Marysya12 [62]

Answer:

i wish i could help but its kind of over a minute but the answer is C

6 0
3 years ago
SOLVE EACH SYSTEM USING SUBSTITUTION
NNADVOKAT [17]
1. since the equations equal each other 
2x+19=x+7
-x        -x
x+19=7
  -19  -19
x= -12
sub into y= x+7
y= -12+7
y= -5

2. x+2y=-7
<span>x+y+23=0
i don't know what the second equation is equal to, i'll assume 0

2y=x-7
y=1/2x-7/2
sub this into x+y+23=0
x+1/2x-7/2+23=0
3/2x+39/2=0
       -39/2   -39/2
3/2x= -39/2
x=-39/2 / 3/2
x= -13
sub into y=1/2x-7/2
y=1/2(-13)-7/2
y= -10

3. </span>x+5y=2
<span>x=-4y+5
</span>sub x=-4y+5 into x+5y=2
-4y+5+5y=2
y+5=2
  -5  -5
y= -3
sub y =-3 into x =-4y+5
x=-4(-3)+5
x= 17

4. 3x+y=9
<span>y=-5x+9
</span>sub -5x+9 into 3x+y=9
3x+(-5x+9)=9
3x-5x+9=9
-2x+9=9
     -9  -9
-2x=0
x=0
sub into y=-5x+9
y=-5(0)+9
y=9

3 0
3 years ago
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