Please help thanks very very much.
1 answer:
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-----> A<span>ny number at all with a 0 exponent is 1; anything with a -ve exponent means "1 over" i.e. 5^-1 means 1/5, 23^-4 means 1/23^4 etc.
</span>----->A number to the power of zero is always 1
<span>A number to the power of a negative number such as 2^-4 is always the reciprocal to the power of 4 so 2^-4 is in fact (1/2) ^4 = 1/2^4 </span>
<span>3^-3/4 is (1/3)^3/4 </span>
<span>(4/9)^-3/5 is (9/4)^3/5
</span>
--->Any number with a zero exponent is equal to 1. A number n to the -x is equal to 1/(n^x)<span>
To simplify a negative exponent expression , I attached an example it is easier that way :)
Hope that helps.xoxo
</span>
</span>----->A number to the power of zero is always 1
<span>A number to the power of a negative number such as 2^-4 is always the reciprocal to the power of 4 so 2^-4 is in fact (1/2) ^4 = 1/2^4 </span>
<span>3^-3/4 is (1/3)^3/4 </span>
<span>(4/9)^-3/5 is (9/4)^3/5
</span>
--->Any number with a zero exponent is equal to 1. A number n to the -x is equal to 1/(n^x)<span>
To simplify a negative exponent expression , I attached an example it is easier that way :)
Hope that helps.xoxo
</span>
Answer:
The first three nonzero terms in the Maclaurin series is
Step-by-step explanation:
GIven that:
The Maclaurin series of cos x can be expressed as :
From equation(1), substituting x with (4x), Then:
The first three terms of cos (4x) is:
Multiplying equation (2) with (3); we have :
Finally , multiplying 5 with ; we have:
The first three nonzero terms in the Maclaurin series is