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Mariulka [41]
3 years ago
6

Find the perimeter of the given triangle

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

Here it is given that the triangles ABP and DCR are similars, therefore we use the ratio rule which states that

corresponding sides of similar triangles are in same proprtion .

\frac{AB}{DC} = \frac{BP}{CR}

that gives

7/10 = BP/11

7*11=10BP

BP=7.7

Again using the ratio rule

\frac{AB}{DC} = \frac{AP}{DR}

7/10 = AP/6

42 = 10AP

AP = 4.2

Perimeter= AB+BP+AP = 7+7.7+4.2 = 18.9

Correct option is A.

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6 0
3 years ago
What is the rule used to reflect the triangle ABC to its image?
Debora [2.8K]

Answer:

The rule used to reflect Δ ABC to its image is Reflect over y = x ⇒ B

Step-by-step explanation:

  • If the point (x, y) reflected across the x-axis , then its image is (x, -y)
  • If the point (x, y) reflected across the y-axis , then its image is (-x, y)
  • If the point (x, y) reflected across the line y = x , then its image is (y, x)
  • If the point (x, y) reflected across the line y = -x , then its image is (-y, -x)

From the given figure

∵ The coordinates of point A are (-4.5, 6)

∵ The coordinates of point A' are (6, -4.5)

→ The coordinates are switched ⇒ 3rd rule

∴ Point A is reflected over the line y = x

∴ Δ ABC is reflected over the line y = x

∴ The rule used to reflect Δ ABC to its image is Reflect over y = x

<em>Note: Point B' on the graph should be C' and point C' should be B' (correct it)</em>

3 0
3 years ago
Which table represents a quadratic relationship?
svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0
4 years ago
Read 2 more answers
Putting recipe makes 4 1/2 cups of pudding. How many 1/3 cup servings does this equal?
mel-nik [20]

Answer:

C

Step-by-step explanation:

First, write 4 ½ in improper form.  2 × 4 + 1 = 9. So the fraction is 9/2.

Now divide:

9/2 ÷ 1/3

To divide by a fraction, multiply by the reciprocal:

9/2 × 3/1

27/2

13 1/2

Answer C.

4 0
3 years ago
Read 2 more answers
A trapezoid has 9.2 inches base and 3.5 inches base, as well as 17 inches height. What is the area?
Tju [1.3M]
107.95in^{2}


The area of a trapezoid is as follows: 

A = \frac{a + b}{2} h

A and B are the lengths of the parallel lines of trapezoids. The parallel lines in this problem are 3.5 and 9.2. After adding those and dividing by 2, we multiply 17 to find the area of the trapezoid. (This is also shown in the attached picture) 

4 0
4 years ago
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