Help please asap?!?!?!

Mathematics

1 answer:

Gwar [14]4 years ago

3 0

In similar figures, the angle measures are the same but the side lengths are different. So in #4, x = 42. Since all the angles of a quadrilateral added up equal 360, then y is 360-90-90-42=138. For number 5, make sure you match up the sides correctly in your ratio: $\frac{2}{x}= \frac{4}{8}$ . You could cross multiply to get 4x=16, and x = 4, or you could just realize that reducing 4/8 will give you 2/4 and x = 4. Going back to the idea that in similar shapes corresponding angles are the same measure, x in #6 is 63

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Lukas wants to create a triangle with sides measuring 9 in 13 in and 15 in he says that more than one triangle is possible given

Karolina [17]

Answer: Lukas is incorrect. The side lengths do not satisfy the triangle inequality rule so no triangles can be drawn given these side lengths.

Step-by-step explanation:

Here is the complete question

Lukas wants to create a triangle with sides measuring 9 in., 13 in., and 15 in. He says that more than one triangle is possible given these side lengths. Which statement about Lukas’s claim is true?

A. Lukas is incorrect. The side lengths satisfy the triangle inequality rule so one unique triangle can be drawn.

B. Lukas is incorrect. The side lengths do not satisfy the triangle inequality rule so no triangles can be drawn given these side lengths.

C. Lukas is correct. The side lengths satisfy the triangle inequality rule so multiple triangles can be drawn.

D. Lukas is correct. The side lengths do not satisfy the triangle inequality rule so multiple triangles can be drawn.

For the figures to make up a triangle, the addition of the square of the two smaller sides must be equal to the square of the larger side. The Pythagoras rule is used.

The figures here are 9, 13 and 15. So let's yes to confirm.

9^2 + 13^2 = 15^2

81 + 169 = 225

250 = 225

Since the two figures are not equal, it is incorrect no triangles can be drawn from the length.

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3 years ago

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serg [7]

Answer:

Step-by-step explanation:

3 0

4 years ago

the vertices of a feasible region are (1,0) (5,5) and (5,0) . what is the maximum value of the function P=2x-y?

wariber [46]

The maximum value of the function is 10

<h3>How to determine the maximum value?</h3>

The function is given as:

P = 2x - y

The feasible regions are given as:

(1,0), (5,5) and (5,0)

Substitute these values in P = 2x - y

P = 2(1) - 0 = 2

P = 2(5) - 5 = 5

P = 2(5) - 0 = 10

The maximum value in the above computation is 10

Hence, the maximum value of the function is 10