Answer:

*Note c could be written as a/b
Step-by-step explanation:
-sin(-t - 8 π) + cos(-t - 2 π) + tan(-t - 5 π)
The identities I'm about to apply:



Let's apply the difference identities to all three terms:
![-[\sin(-t)\cos(8\pi)+\cos(-t)\sin(8\pi)]+[\cos(-t)\cos(2\pi)+\sin(-t)\sin(2\pi)]+\frac{\tan(-t)-\tan(5\pi)}{1+\tan(-t)\tan(5\pi)}](https://tex.z-dn.net/?f=-%5B%5Csin%28-t%29%5Ccos%288%5Cpi%29%2B%5Ccos%28-t%29%5Csin%288%5Cpi%29%5D%2B%5B%5Ccos%28-t%29%5Ccos%282%5Cpi%29%2B%5Csin%28-t%29%5Csin%282%5Cpi%29%5D%2B%5Cfrac%7B%5Ctan%28-t%29-%5Ctan%285%5Cpi%29%7D%7B1%2B%5Ctan%28-t%29%5Ctan%285%5Cpi%29%7D)
We are about to use that cos(even*pi) is 1 and sin(even*pi) is 0 so tan(odd*pi)=0:
![-[\sin(-t)(1)+\cos(-t)(0)]+[\cos(-t)(1)+\sin(-t)(0)]+\frac{\tan(-t)-0}{1+\tan(-t)(0)](https://tex.z-dn.net/?f=-%5B%5Csin%28-t%29%281%29%2B%5Ccos%28-t%29%280%29%5D%2B%5B%5Ccos%28-t%29%281%29%2B%5Csin%28-t%29%280%29%5D%2B%5Cfrac%7B%5Ctan%28-t%29-0%7D%7B1%2B%5Ctan%28-t%29%280%29)
Cleaning up the algebra:
![-[\sin(-t)]+[\cos(-t)]+\frac{\tan(-t)}{1}](https://tex.z-dn.net/?f=-%5B%5Csin%28-t%29%5D%2B%5B%5Ccos%28-t%29%5D%2B%5Cfrac%7B%5Ctan%28-t%29%7D%7B1%7D)
Cleaning up more algebra:

Applying that sine and tangent is odd while cosine is even. That is,
sin(-x)=-sin(x) and tan(-x)=-tan(x) while cos(-x)=cos(x):

Making the substitution the problem wanted us to:

Just for fun you could have wrote c as a/b too since tangent=sine/cosine.
Hello :
f(r) = πr².... r <span> <span>><span> 0
</span></span></span>the domain is : <span>] 0; + ∞[<span> </span></span>
Answer:
h = 64 feet
Step-by-step explanation:
If you graph the function you see that 64 feet is the maximum of the parabola so this is the max height that the projectile reaches.
The exact answer is 123.592105263
Hope This Helps You!
Good Luck Studying :)
Answer:
The formula to solve this would be:
X x Y = 13
There are at least two combinations of two numbers that you can multiply together to get 13.
Step-by-step explanation: