A. p = 5t + 4 b. a = t2 - 4 c. d = t(5 – f) Make t the subject in the formulas
1 answer:
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Answer:
Therefore the required resulting equation is
6 x minus 15 y = negative 63.
Negative 15 x + 15 y = 90
Step-by-step explanation:
Given:
......................Equation ( 1 )
......................Equation ( 2 )
To Find:
Expression after multiplying to eliminate y term,
Solution:
So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5, such that equations becomes
.....( 1 )
.....( 2 )
so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,
Therefore the required resulting equation is
6 x minus 15 y = negative 63.
Negative 15 x + 15 y = 90