answer = the elder bother is 17 and the younger one is 15
constructive odd integers= 15 and 17
17×15= 255
255+38 = 293
Square root of 293 = 17
35x - 63 + 4x
35x + 4x -63
39x - 63
There are 10 matches in the competition if you count every other player you'll end up with 10
X+y = 4, therefore y = 4-x when you rearrange the equation.
You can subsitute this in: x-(4-x) = 6
-4+x = 6-x
x=10-x
2x = 10
x = 5
Substitute x into the previous equation:
5+y = 4
y = 4-5
y = -1
