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3 years ago

There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red

Mathematics

1 answer:

madam [21]3 years ago

3 0

Answer:

The probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble = $\frac{12}{20}$

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble = $\frac{8}{19}$

So, the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag = $\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}$

Hence the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95

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3 years ago

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2 years ago

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Step-by-step explanation:

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