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4 years ago

There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red

Mathematics

1 answer:

madam [21]4 years ago

3 0

Answer:

The probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble = $\frac{12}{20}$

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble = $\frac{8}{19}$

So, the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag = $\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}$

Hence the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95

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35. In a simple random sample of 25 high school students, the sample mean of the SAT scores was 1450, and the sample variance wa

Tatiana [17]

Answer:

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

Step-by-step explanation:

Information provided

$\bar X=1450$ represent the sample mean for the SAT scores

$\mu$ population mean (variable of interest)

$s^2 = 900$ represent the sample variance given

n=25 represent the sample size

Solution

The confidence interval for the true mean is given by :

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The sample deviation would be $s=\sqrt{900}= 30$

The degrees of freedom are given by:

$df=n-1=2-25=24$

The Confidence is 0.954 or 95.4%, the value of $\alpha=0.046$ and $\alpha/2 =0.023$ , assuming that we can use the normal distribution in order to find the quantile the critical value would be $z_{\alpha/2} \approx 2.0$

The confidence interval would be

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

3 0

3 years ago

A king owned land outside of his castle he has partitioned the land to give as gifts to his 5 sons what fraction of land did the

siniylev [52]

Answer:

1/5

Step-by-step explanation:

since there is 5 sons they divide the land in 5.

4 0

3 years ago

Can someone pls help me / alguien me puede ayudar

user100 [1]

Answer:

The simplified expression is:

$\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)=0.2y+0.2x-8$

Step-by-step explanation:

Given the expression

$\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{2}{5}y+\frac{1}{5}x-0.2y-6-2$

$\mathrm{Group\:like\:terms}$

$=\frac{2}{5}y-0.2y+\frac{1}{5}x-6-2$

Add similar elements

$=0.2y+\frac{1}{5}x-6-2$

$=0.2y+\frac{x}{5}-6-2$

$=0.2y+\frac{x}{5}-8$

$=0.2y+0.2x-8$

Thus, the simplified expression is:

$\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)=0.2y+0.2x-8$

6 0

3 years ago

Inez and Roy made three numbers with their number cards .Then their table got bumped and mixed up the three numbers again.One nu

Misha Larkins [42]

The greatest six-digit number they could make is 998,877 I know this because I used the largest digits and put them in order from largest to smallest.

Hope this helps

6 0

3 years ago

Jeremy’s fruit stand sells peaches and watermelons. In the first hour the fruit stand is open, 12 bushels of peaches and 5 water

polet [3.4K]

We define the variables:
p: cost of bushel of peaches
w: cost of watermelon
We wrote the system of equations:
12p + 5w = 150
15p + 8w = 198
We can represent the system in matrix form as
Ax = b
Where,
A = [12 5; 15 8]
b = [150; 198]
x = [p; w]

3 0

3 years ago

Read 2 more answers