Question

There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red

Answer 1

Answer:

The probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble =$\frac{12}{20}$

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble =$\frac{8}{19}$

So, the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag =$\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}$

Hence the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95