<span>He should use the mean because there are no outliers that affect the mean.</span>
The probability of picking a green jelly bean with the first pick is 4/14 = 2/7, because there are 14 jelly bean in total (6 red + 4 green + 4 blue) and 4 of them are green.
If you pick a green jelly bean at the beginning, you have 13 jelly beans remaining, of which 6 are red. So, the probability of picking a red jelly bean is now 6/13.
You want these two events to happen one after the other, to be more precise you want to pick a green jelly bean with the first pick AND a red jelly bean with the second pick. We know the probabilities of the two events, so we have to multiply them to get the probability of them happening both:

12n * 2 = 24n
4n * 3 = 12n
(Simplifying the multiplication parts)
12n - 24n = -12n
-12n - 7n = -19n
(Simplifying the subtracting/Addition parts)
9 = 9
(You can't simplify the 9)
9 - 19n
(Putting it all together)
Hope This helps! :)
Answer:
this cannot be simplified is the best answer
Step-by-step explanation:
The answer i got is -(tan(x)+1)(tan(x)-1) / tan^2(x)
Line segment of length k is divided into 3 equal parts.
so first segment is 0-k/3 and third segment is 2/3k-k
so mid-pt of 1st = k/6 and 3rd = 5/6k
so the distance in between = 5/6k-k/6 = 4/6k = 2/3k
ans is A