the answer to this question is -8
1. y = 4x - 3
2. y = -x + 4
3. y = 1/3x +1
4. y = ----
5. y = 1/7x + 2
6. y = -4x + 2.75
7. y = 3x + 5
8.
9.
10.
11.
12.
If te squre is inscribe in the cercle ten:The area of the circle is πR²
& the Area of te square is 2R², then the probability to land in the square :
2R²/πR²=2/π=0.6366 or 63.66%
Answer:
3/2 < x < 2
Step-by-step explanation:
We assume the problem is ...
[tek]\dfrac{1}{x-2}<-2[/tex]
This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...
1 > -2(x -2)
1 > -2x +4
2x > 3 . . . . . . add 2x-1
x > 3/2
From above, we also have x < 2, so the solution set is ...
3/2 < x < 2
Answer:
The original selling price was
Step-by-step explanation:
Let
x-----> the original selling price
we know that

so
-----> equation that represent the situation
solve for x
Divide by 0.80 both sides