All categories

3 years ago

Determine if the following relation is a function.

Mathematics

2 answers:

Mama L [17]3 years ago

3 0

Yes it is a function

Free_Kalibri [48]3 years ago

3 0

Answer:

It is a function.

Step-by-step explanation:

It is proven via the vertical line test.

You might be interested in

Alex is working to simplify

stich3 [128]

Answer:

is this all?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the equation for 5 units left and 3 units up from f(x)=x

erastovalidia [21]

The new equation after shifting will be:

$g(x) = (x+5)+3\\g(x) = x + 8$

Step-by-step explanation:

Function trnafomations upward and left are defined as:

Upward:

f(x) => f(x)+b where b is an integer

Left:

f(x) => f(x+b) where b is an integers

Given function is:

$f(x) = x$

Shifting the function 5 units left

$g(x) = f(x+5) => x+5\\g(x) = x+5$

Shifting the function upward 2 units

So,

$g(x) = (x+5)+3\\g(x) = x + 8$

The new equation after shifting will be:

$g(x) = (x+5)+3\\g(x) = x + 8$

Keywords: Functions, shifting

Learn more about functions at:

#LearnwithBrainly

3 0

3 years ago

Find the dot product of v=-7i+4j and w=-6+5j

Anna35 [415]

V•w = (-7i +4j)•(-6i +5j) = (-7)×(-6) +4×5 = 42 +20
v•w = 62

6 0

3 years ago

In the figure, mm is parallel to n and r is a transversal. If m=45 degrees, find the measure of each angle.

Zigmanuir [339]

Angle A = 45, it’s opposite angle is 45
It’s adjacent is 135 degrees for total of 180 on each parallel line

6 0

2 years ago

Why can’t we use the rules for exponents when the bases are not common?

Kazeer [188]

Answer:

Ok, the rules of the exponent come from a logic construction.

If we have x^n

this means that n is multiplied by itself n times.

If we decompose n into a + b, we have:

x by itself a times, and then x by itself b times, and for how the product works, this is equivalent:

if n = 5, a= 2 and b = 3

x^5 = (x*x*x*x*x) 5 times-

x^5 = x^(2 + 3) = (x^2)*(x^3) = (x*x*)*(x*x*x) = x*x*x*x*x = x^5

And the same for the other rules:

(x^n)^b = x^n*b and such.

Obviusly, this only works when we have a common base.

So the correct answer is that we constructed the exponential rules in a way that only can be used when we have a common base, and this happens because to construct them, we started with common bases.

4 0

3 years ago