The answer should be physical<span />
The investigation using solid and liquid water to show that thermal energy is not the same as temperature is:
- Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.
<h3>What is the response to the experiment above?</h3>
The response is No, because the lake is known to have a lot more particles than the glass of water and so they will not have the same thermal energy.
Note that the temperature is seen as the an average and thermal energy is seen to be the total. A glass of water can be able to have the same temperature as what we call Lake Superior, but the lake has a lot of thermal energy due to the fact that the lake has a lot of water molecules.
So the investigation using solid and liquid water to show that thermal energy is not the same as temperature is Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.
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Since the compound is 72.2% Mg then there would be 27.8% N. Then you can just change it to 72.2 g Mg and 27.8 g N.
then convert to moles by dividing by molecular mass.
72.2÷24.31=2.96 moles Mg
27.8÷14.01=1.98 moles N
then divided by the lowest number.
2.96÷1.98=1.5
Since it is 1.5 you multiply by 2. so you have 3 Mg
1.98÷1.98=1 N
so the empirical formula is Mg3N
Hello there,
The number placed below an element's symbol in a chemical formula is called....
a subscript
Hope I Helped!
-Char
a. 1.05 x 10⁻³ mol
b. 0.155% w/v
<h3>Further explanation</h3>
Given
50 ml Ca(OH)₂
19.5 ml of 0.1059 N HCl
Required
Amount of Ca(OH)₂
The Ca(OH)₂ concentration in % w/v.
Solution
Titration formula :
M₁V₁n₁=M₂V₂n₂
or
N₁V₁=N₂V₂
n = acid base valence=amount of H⁺/OH⁻(Ca(OH)₂=2, HCl=1)
a.
Input the value(1=Ca(OH)₂, 2= HCl) :
M₂=N₂=0.1059 M
M₁. 50 ml . 2 = 0.1059 . 19.5 . 1
M₁ = 0.021
Amount of Ca(OH)₂ :
mol Ca(OH)₂ = 0.021 x 50 ml = 1.05 mlmol = 1.05 x 10⁻³ mol
b. mass of Ca(OH)₂
= mol x MW
= 1.05 x 10⁻³ mol x 74 g/mol
= 0.0777 g
%w/v = (g solute / volume of solution) x 100
%w/v =( 0.0777 g/ 50 ml) x 100 =0.155% w/v