The alkane with six carbon atoms is called hexane. butane. butene. heptane. none of these choices is correct.

Chemistry

1 answer:

Mkey [24]2 years ago

7 0

Option(A) is the correct answer.

The alkane with six carbons is called hexane.

<h3>What are the potential hazards of hexane?</h3>

Hexane is used as a special-purpose solvent, a cleaning agent, and to extract edible oils from seeds and vegetables. Humans who are acutely (short-term) inhaled high quantities of hexane have moderate central nervous system (CNS) symptoms such giddiness, nausea, headache, and dizziness. Humans who are exposed to hexane in the air <u>over an extended period of time</u> may develop polyneuropathy, which manifests as numbness in the extremities, muscle weakness, impaired vision, headaches, and tiredness. Rats have also displayed neurotoxic consequences. Hexane's potential to cause cancer in both humans and animals is unknown. Hexane has been categorized by the EPA as Group D, not classifiable as a human carcinogen.

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Atoms in the same _____ of the periodic table share the same chemical properties

Mila [183]

I'm taking the same quiz. The answer is column

5 0

4 years ago

6. Under standard-state conditions, what spontaneous reaction will occur in aqueous solution among the ions Ce4+, Ce3+, Fe3+, an

xz_007 [3.2K]

Answer:

ΔG° = -80.9 KJ

Assuming this reaction takes place at room temperature (25 °C):

K= $1.53x10^{14}$

Explanation:

1) Reduction potentials

First of all one should look up the reduction potentials for the species envolved:

$Ce^{4+} + e$ → $Ce^{3+}$ E°red=1.61V

$Fe^{3+} + e$ → $Fe^{2+}$ E°red=0.771V

2) Redox pair

Knowing their reduction pontentials one can determine a redox pair: one species must oxidate while the other is reducing. <u>Remember: the table gives us the reduction potential, so if we want to know the oxidation potential all that has to be done is reverce the equation and change the potencial signal (multiply to -1).</u>

1) $Ce^{4+}$ reduces while $Fe^{2+}$ oxidates

(oxidation) $Fe^{2+}$ → $Fe^{3+} + e$ E°oxi=-0.771V

(reduction) $Ce^{4+} + e$ → $Ce^{3+}$ E°red=1.61V

(overall equation) $Fe^{2+}+Ce^{4+}$ → $Ce^{3+}+Fe^{3+}$ E°=Ereduction + Eoxidation= 1.61 v+(-0.771 v) = 0.839v

The cell potential can also be calculated as the cathode potencial minus the anode potential:

E° = E cathode - E anode =1.61 v - 0.771 v=0.839 v

3) Gibbs free energy and Equilibrium constant

ΔG°=-nFE°, where 'n' is the number of electrons involved in the redox equation, in this case n is 1. 'F' is the Faraday constant, whtch is 96500 C. E° is the standard cell potencial.

ΔG°=-nFE°=-1*96500*0.839

ΔG° = - 80963 J = -80.9 KJ

The Nerst equation gives us the relation of chemical equilibrium and Electric potential.

E=E°- $\frac{RT}{nF} Ln Q$