Answer:
x < 1 and y < -2
Step-by-step explanation:
Answer:
Simplification of algebric expression is 
Step-by-step explanation:
Simplify any algebric expression means to write an equivalent expression in which all similar terms combined and remove all symbols such as brackets.
The given algebraic equation is 
now for simplifying it
First of all take L.C.M of 
= 
We get 
Further we can write it as 
Simplification of algebric expression is 
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Answer:
Step-by-step explanation:
let us calculate area of pentagon.
it consists of 5 isosceles triangles with base=5 cm
apothem h=3.6 cm
area of pentagon=5×1/2×5×3.6≈45 cm
area of 2 pentagons (top and bottom)=2×45=90 cm²
lateral area of 6 rectangles=2(10×5+10×5+10×5)=2(50+50+50)=300 cm²
Total surface area=90+300=390 cm²
Answer:
tan A = <u>opp</u>
adj
tan G = <u>EF</u>
3
from Pythagoras theorem,
EF² + 3² = (√24)²
EF² + 9 = 24
EF² = 15
EF = √15
then,
tan G = <u>√</u><u>1</u><u>5</u>
3
therefore tan G = √15/3
-3 | 1 0 0 0 0 243

coefficients of the polynomial you're dividing
. |

drop down the leading coefficient
- - - - - - - - - - - - - - - - - - -
. | 1
On the left side of the frame, we write -3 because we're dividing by

. (The algorithm is followed for division of a polynomial by a factor of

.) Since we're dividing a degree 5 polynomial by a degree 1 polynomial, we expect to get a degree 4 polynomial.
-3 | 1 0 0 0 0 243
. | -3

multiply -3 by 1, write in next column, add to 0
- - - - - - - - - - - - - - - - - - -
. | 1 -3
Repeat step for the remaining columns.
-3 | 1 0 0 0 0 243
. | -3 9
- - - - - - - - - - - - - - - - - - -
. | 1 -3 9
-3 | 1 0 0 0 0 243
. | -3 9 -27
- - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27
-3 | 1 0 0 0 0 243
. | -3 9 -27 81
- - - - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27 81
-3 | 1 0 0 0 0 243
. | -3 9 -27 81 -243
- - - - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27 81 0
which translates to

So the bottom row of the frame gives the coefficients of each term in the quotient by descending order. Since the last coefficient is 0, this means the remainder upon division vanishes, i.e.

is exactly divisible by

.
- - -
Another way to get the same result is to use a well-known result: for

,

and in this case

and