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natka813 [3]
2 years ago
10

PLZ HELP ILL MARK YOU BRAINLIEST

Mathematics
1 answer:
NARA [144]2 years ago
7 0

Answer:

D. 89°

Step-by-step explanation:

On the line segment "C,"  89 degrees is shown in one corner. x is directly across from it, therefore being the same degrees

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HELP ASAP!!!! simplify 3^2-4/5
My name is Ann [436]

Answer:

9-4/5

5/5 = 1

Step-by-step explanation:

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2 years ago
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What is the surface area of this triangular prism? The base of each triangle is 42 m and the height of the triangular base is 20
shutvik [7]

<u>Given</u>:

The base of each triangular base is 42 m.

The height of each triangular base is 20 m.

The sides of the triangle are 29 m each.

The height of the triangular prism is 16 m.

We need to determine the surface area of the triangular prism.

<u>Surface area of the triangular prism:</u>

The surface area of the triangular prism can be determined using the formula,

SA=bh+(s_1+s_2+s_3)H

where b is the base of the triangle,

h is the height of the triangle,

s₁, s₂ and s₃ are sides of the triangle and

H is the height of the prism.

Substituting the values, we get;

SA=(42)(20)+(42+29+29)(16)

SA=840+(100)(16)

SA=840+1600

SA=2440

Thus, the surface area of the triangular prism is 2440 m²

8 0
3 years ago
Graph the line y = 3x
ollegr [7]

Answer:

literally google graphing calculator and type 3x

7 0
2 years ago
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What is the difference between explicit and recursive sequences ?
Anna71 [15]
An explicit formula for a sequence allows you to find the value of any term in the sequence. A recursive formula for a sequence allows you to find the value of the nth term in the sequence if you know the value of the (n-1)th term in the sequence.
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2 years ago
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Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor
Liula [17]

Answer:

(AD)^2 + (CD)^2 = (CA)^2 and (CD)^2 + (BD)^2 = (CB)^2

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

Hypothenuse = CA

Opposite = CD

Adjacent = AD

By Pythagoras Theorem, we have

(AD)^2 + (CD)^2 = (CA)^2

Considering CBD

From the attachment, we have that:

Hypothenuse = CB

Opposite = CD

Adjacent = BD

By Pythagoras Theorem, we have:

(CD)^2 + (BD)^2 = (CB)^2

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2 years ago
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