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nexus9112 [7]
3 years ago
6

A spy is trying to escape. She must get by four guards. Each guard takes half of her remaining money. She then $64 for her plane

ticket. How much money does she have to start with in order to make her escape?
Mathematics
1 answer:
Komok [63]3 years ago
5 0

Answer:

The spy must have at the start the amount of $1,024 in order to escape

Step-by-step explanation:

Let

a ------> amount of money that the spy must have at the start to escape

y ----> the remaining money

x ----> the number of guards

In this problem the remaining money is going to be reduced by half, every time the spy passes through a guard, so we can use an exponential function of the form

y=a(b^{x})

where

a is the initial value (amount of money at the start)

b is the base

b=(1-r)

r is the rate of decay

In this problem we have

r=50% -----> r=0.50

The value of b is

b=(1-0.50)=0.50

substitute

y=a(0.50^{x})

we know that

In order to escape after the fourth guard the amount of money remaining must be equal to $64

so

For x=4, y=$64

substitute in the equation and solve for a

64=a(0.50^{4})

64=a(0.0625)

a=64/(0.0625)

a=\$1,024

therefore

The spy must have at the start the amount of $1,024 in order to escape

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Step-by-step explanation:

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To solve: 4y+4y+(3y+14)=180

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11y=166

Divide by 11

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6 0
3 years ago
3. triangle abc has angle measures as shown (look at image).
mart [117]

Answer:

x = 6, ∠B = 50°

Step-by-step explanation:

a) 8x + 2 + 70 + 60 = 180

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8x = 180 - 132 = 48

x = 48/8 = 6

b) ∠B = 180 - 70 - 60 = 50°

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3 0
2 years ago
What is the answer to this equation, p - 1.34 = -11.8
Nana76 [90]
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8 0
3 years ago
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Please answer this correctly
vovangra [49]

Answer:

Cable: 10%  Satellite: 40%  Streaming Service: 50%

Step-by-step explanation:

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5 0
3 years ago
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Is x-10 a factor of f(x)=5x^3+60x^2+109x+90
RUDIKE [14]

Answer:

No

Step-by-step explanation:

Given values are

f(x) = 5x^3+60x^2+109x+90

x = -10.

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By putting x = (-10) we can rewrite it as

= (90)+(5.(-10)^3)+(60.(-10)^2)+(109.(-10))

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= 0

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4 0
3 years ago
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