Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer: 315
Step-by-step explanation: hope this is right.
7x+6=3x-6
+6 +6
7x+12=3x
-3x -3x
4x+12=0
-4x -4x
divide both sides by -4 but you have to flip the sign.
-3>x
or
{x | x < -3}
Step-by-step explanation:
The answer is in the picture
