Find the zeros of the function f(x)=2x^2-4x-2.9 to the nearest hundredth
1 answer:
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Answer:
x = 18
y = 5
Step-by-step explanation:
From the figure attached,
'l' and 'm' are the parallel lines and two transversal lines are intersecting these parallel lines at points A, B and C.
Since, m∠ABC + (7x - 23)° = 180° [Supplementary angles]
m∠ABC = 180° - (7x - 23)°
m∠BCA = (11y - 1)° [Vertical angles]
m∠BAC = 49°
In ΔABC,
m∠ABC + m∠BAC + m∠CAB = 180°
180° - (7x - 23)° + 49° + (11y - 1) = 180°
-7x + 11y = -71
7x - 11y = 71 ------(1)
Since, sum of consecutive angles is 180°
Therefore, m(∠ABC) + (3x + 49)° = 180°
180° - (7x - 23)° + (3x + 49)° = 180°
-4x = -72
x = 18
From equation (1),
7(18) - 11y = 71
11y = 55
y = 5
