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tester [92]
3 years ago
10

Solve each equation for y. Then find the value of y for each value of x. y+3x=8;x=-2,0,2

Mathematics
1 answer:
damaskus [11]3 years ago
6 0
Y=-3x+8
when x=-2:
y=-3(-2)+8
y=6+8
y=14
when x=0
y=-3(0)+8
y=0+8
y=8
when x=2
y=-3(2)+8
y=-6+8
y=2
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X^2-4x+3=0 write it in standard form.
trasher [3.6K]

Answer:

x

=

2

±

√

7

Explanation:

there are no whole numbers which multiply to - 3

and sum to - 4

we can solve using the method of  

completing the square

the coefficient of the  

x

2

term is 1

∙

add subtract  

(

1

2

coefficient of the x-term

) 2  to x2 − 4 x ⇒ x 2 +2(− 2 ) x + 4 − 4 − 3 = 0 ⇒ ( x − 2 )2 − 7 =0 ⇒ ( x − 2 ) 2 = 7

take the square root of both sides

⇒ x − 2 = ± √ 7 ←

note plus or minus

⇒ x = 2 ± √ 7←

exact solutions

4 0
3 years ago
Read 2 more answers
-10x—16=14<br> -16x -6 = 14
Alla [95]

Answer: No solution

Step-by-step explanation:

-10x-16=14

-16x-6=14

-10x-16=-16x-6

-10x+16x-16=-16x+16x-6

6x-16=-6

6x-16+16=-6+16

6x=10

x=10/6

x=5/3

-16(5/3)-6=

-80/3-6*3/3=

-80/3-18/3=

(-80-18)/3=-98/3 \neq 14

Hence, there is no solution

4 0
1 year ago
Rewrite these problems using a negative exponent, ill give brainliest
Ira Lisetskai [31]

Answer:

I have made it in above picture hope it helps

8 0
3 years ago
Read 2 more answers
Math Problem w Quadratics
oee [108]
Opyion B hope this help!
8 0
3 years ago
You need to design a rectangle with a perimeter of 14.2 cm. The length must be 2.4 cm. What is the width of the
irina1246 [14]

Part (a)

<h3>Answer: 2(2.4+w) = 14.2</h3>

--------------

Explanation:

L = 2.4 = length

W = unknown width

The perimeter of any rectangle is P = 2(L+W)

We replace L with 2.4, and replace P with 14.2 to get 14.2 = 2(2.4+w) which is equivalent to 2(2.4+w) = 14.2

========================================================

Part (b)

<h3>Answer:   w = 4.7</h3>

--------------

Explanation:

We'll solve the equation we set up in part (a)

2(2.4+w) = 14.2

2(2.4)+2(w) = 14.2

4.8+2w = 14.2

2w = 14.2-4.8

2w = 9.4

w = 9.4/2

w = 4.7

The width must be 4.7 cm.

4 0
3 years ago
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