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tester [92]
3 years ago
10

Solve each equation for y. Then find the value of y for each value of x. y+3x=8;x=-2,0,2

Mathematics
1 answer:
damaskus [11]3 years ago
6 0
Y=-3x+8
when x=-2:
y=-3(-2)+8
y=6+8
y=14
when x=0
y=-3(0)+8
y=0+8
y=8
when x=2
y=-3(2)+8
y=-6+8
y=2
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Evaluate 8-2.<br>A. -16<br>B. -64<br>C. -1/64<br>D. 1/64<br> ​
makvit [3.9K]

I'm assuming you meant to write 8^(-2) or 8^{-2} where the -2 is the exponent over the 8.

If my assumption is correct, then we use the rule a^{-b} = \frac{1}{a^b}

So,

a^{-b} = \frac{1}{a^b}\\\\8^{-2} = \frac{1}{8^2}\\\\8^{-2} = \frac{1}{64}

<h3>Answer: Choice D.  1/64</h3>
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2 years ago
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vfiekz [6]

so maybe 6 plus 3 which equals 9. Then add 8 at the end

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4 years ago
odd function f(x) is defined for all real values of x. for the function g(x)=2.3+f(x-9), calculate g(6)+g(8)+g(10)+h(12).
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Answer:

easy theanswer is -14x

Step-by-step explanation:

4 0
3 years ago
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Answer:

<u><em>The relative frequency of rolling a particular number can be calculated using the formula </em></u>

<u><em> </em></u>

<u><em>relative frequency , where f is the actual frequency of an event and n is the number of times the experiment is performed. This experiment had the following results: </em></u>

<u><em> </em></u>

<u><em>The relative frequency of rolling a 1 is 0.2. </em></u>

<u><em>The relative frequency of rolling a 2 is about 0.23. </em></u>

<u><em>The relative frequency of rolling a 3 is about 0.13. </em></u>

<u><em>The relative frequency of rolling a 4 is 0.15. </em></u>

<u><em>The relative frequency of rolling a 5 is 0.15. </em></u>

<u><em>The relative frequency of rolling a 6 is about 0.13. </em></u>

<u><em>The relative frequencies of rolling 1, 2, 3, 4, 5, and 6 are quite similar. So, the relative frequency is a good predictor of the theoretical probability. </em></u>

Step-by-step explanation:

this is exact answer from edmentum so change it up a bit

6 0
3 years ago
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