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Olin [163]
4 years ago
5

Lavonne sold 4 times as many raffle tickets as kenneth. lavonne sold 56 raffle tickets. how many tickets did kenneth sell?

Mathematics
2 answers:
bonufazy [111]4 years ago
7 0

56÷4=14

Kenneth sold 14 tickets 
torisob [31]4 years ago
5 0

14 is the answer. Just divide 56/4 and you get 14.

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prohojiy [21]

Using the z-distribution, it is found that a sample size of 3,385 is required.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

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In this problem, we have a 98% confidence level, hence\alpha = 0.98, z is the value of Z that has a p-value of \frac{1+0.98}{2} = 0.99, so the critical value is z = 2.327.

We have no prior estimate, hence \pi = 0.5 is used, which is when the largest sample size is needed. To find the sample size, we solve the margin of error expression for n when M = 0.02, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 2.327\sqrt{\frac{0.5(0.5)}{n}}

0.02\sqrt{n} = 2.327 \times 0.5

\sqrt{n} = \left(\frac{2.327 \times 0.5}{0.02}\right)

(\sqrt{n})^2 = \left(\frac{2.327 \times 0.5}{0.02}\right)^2

n = 3,385.

A sample size of 3,385 is required.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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