Acceleration = (change in speed) / (time for the change) .
Change in speed = (25 m/s - 9 m/s) = 16 m/s
Time for the change = (8 sec - 5 sec) = 3 seconds
Acceleration = (change in speed) / (time for the change)
= (16 m/s) / (3 sec)
= (5 and 1/3) m/s² .
(rounded to the nearest hundredth ... 5.33 m/s² . )
Answer:
x = 2
Step-by-step explanation:
-8(x-6) = 32 (distribute)
-8x+48 = 32 (subtract 48 from both sides)
-8x = -16 (divide)
x = 2
Answer:

Step-by-step explanation:
The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be
. The magnitude of
will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is
, we have:
(Recall that
)
Now that we've found the vertical component of the velocity and launch, we can use kinematics equation
to solve this problem, where
is final and initial velocity, respectively,
is acceleration, and
is distance travelled. The only acceleration is acceleration due to gravity, which is approximately
. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.
What we know:
Solving for
:

Answer:
D = -7
Step-by-step explanation: