Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:

Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
There would be 14 female and 7 male, so the total number of students is 21.
Answer:
If f(x) = 3x, this means that any number that replaces x in the parenthesis, would replace x in the right side too.
When x = -1:
f(-1) = 3(-1) = -3
When x = 0:
f(0) = 3(0) = 0
When x = 3:
f(3) = 3(3) = 9
~
If the diagonal is 32 than you will us
A^2 + b^2 = c^2
We will use the aspect ratio to find a common variable
4A = 3B
a = (3/4)B now plug it in
((3/4)B)^2 + b^2 = 32 (This is because c is the diagonal)
Now solve for B
B turns out to be 25.577 inches
Plug B in
A = (3/4)(25.577)
A = 19.18
Now add up ther perimeter A + A + B + B
19.18 + 19.18 + 25.577 + 25.577
89.6 inches
Answer:
10.04 × 8.8 =?, ? = 88.352 :)