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densk [106]
2 years ago
14

Solve the equation. If there is no solution, write no solution. Y + 8 – 2(y – 20) > 0

Mathematics
1 answer:
Pani-rosa [81]2 years ago
4 0
Y+8-2y+40 > 0
-y+48 > 0
-y > -48
y < 48 (symbol changes when divided or multiplied with negative (-))
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Evaluate. -|-7 + 3| <br> 4<br> -4<br> -10
agasfer [191]
Your answer is 4

You have to use the distribute property and distribute the - to the -7 and the 3

The -7 will become and the 3 will become -3

Then you add those together and when you add a negative to a positive you basically subtract

So 7+-3 is 4

A is your answer
3 0
3 years ago
How does -1.125 + 1.2 = 0.075 instead of 0.925?
kenny6666 [7]

Answer:

.0075 (hope this help; let me know if not)

Step-by-step explanation:

The operation is + and the signs of the numbers are opposite so we have to subtract. The bigger number has positive sign in front if so we do 1.2-1.125=1.200-1.125

I'm going to line up

1.200

-1.125

---------

If you have 200 and you take about 125... 75 should beleft

so

1.200

-1.125

---------

0.075

6 0
3 years ago
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
Write a expression for j less than 113
kiruha [24]
So you just need to use the crocodile signs < or >
As j is less than 113 we put j on the smaller side and 113 on the bigger side to make:
j<113
4 0
3 years ago
The zeros of the functions f(x) = 3x^2 - 3x - 6
Butoxors [25]
The answer is: x = 2 ∨ x = -1
7 0
2 years ago
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