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JulijaS [17]
3 years ago
8

When electrons of a chlorophyll molecule are raised to a higher energy level, Select one: a. they become a photon of light. b. t

hey form a glucose bond. c. they enter an electron transport chain. d. carotenoids are converted to chlorophyll.
Biology
1 answer:
Sophie [7]3 years ago
7 0

Answer:

c. they enter an electron transport chain.

Explanation:

The chlorophyll in leaves of   plants undergoing photosynthesis is made up of two pigments ; these are  the primary pigments and the accessory pigments. The latter are arranged around the primary pigments.  These two pigments are arranged in chlorophyll  to form photo systems i and ii. The photosystems   serves as the reaction centers of chloroplast. <u>Basically the accessory pigment absorbs  photons of energy and sends this to the  primary pigments.</u>

When photons of light is absorbed by the chlorophyll of the leaf. The electrons  in the chlorophyll  are excited, and  therefore move to higher energy levels. At this stage they are  said to be  activated.  This process is called Photoactivation.

However, instead of the excited electrons to return to the  photo- systems  so that the acquired energy is lost as heat to the surroundings,  these electrons are  trapped by electron acceptors and  are passed to the electron transport chains. These chains of electrons generate proton motive force PMF, for  pumping protons across the thylakoid membranes , down into the thylakoid for  the synthesis of  ATPs by ATPase synthase; through Chemiosmosis.

The ATP is needed in Calvin's Cycle for Carbohydrates synthesis.

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3 years ago
22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit
mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

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3 years ago
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Answer:

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