An acorn falls from the branch of a tree to the ground 25 feet below. The distance, S, that the acorn is from the ground as it f
alls is represented by the equation S(t) = –16t2 + 25, where t is the number of seconds. For which interval of time is the acorn moving through the air?
The distance ( S ) is represented by the equation: S ( t ) = - 16 t² + 25 - 16 t² + 25 = 0 - 16 t² = - 25 / · ( - 1 ) 16 t² = 25 t ² = 25 / 16 t = √( 25/16) = 5/4 = 1.25 s ( we will not accept the negative value ) Answer: The acorn is moving trough the air for 1.25 seconds.
