P=156 cm
l=6+5w
P=2(l+w)
156=2(6+5w+w)
156=2(6+6w)
156=12+12w
12+12w=156
12w=156-12
12w=144
w=12cm
l=6+5•12
l=6+60
l=66cm
Answer:
B and C
Step-by-step explanation:
Required
Select graphs that are dilated by a scale factor greater than 1
For graph A:
Graph A is smaller than the original graph. This indicates dilation with a scale factor less than 1
For graph B:
Graph B is bigger than the original graph and is dilated over (0,0). This indicates dilation with a scale factor greater than 1
For graph C:
Graph C is bigger than the original graph; however, it is not dilated over (0,0). This indicates dilation with a scale factor greater than 1
For graph D:
Graph D is bigger than the original graph; however, it is not only dilated but also flipped over (i.e. rotated).
<em>Hence, b and c is true</em>
To answer this first we set up a proportion and then solve. Lets do it:-

Cross Multiply:-
80 · 4 = 320
Divide:-
420 ÷ 12 = 60
So, 180 ears of corn are for
$60.Hope I helped ya!!
Answer:
192
Step-by-step explanation:
Multiply 3/4 by 256
Answer:
The towel bar should be placed at a distance of
from each edge of the door.
Step-by-step explanation:
Given:
Length of the towel bar = 
Now given length is in mixed fraction we will convert in fraction.
To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.
can be Rewritten as 
Length of the towel bar = 
Length of the door = 
can be Rewritten as 
Length of the door = 
We need to find the distance bar should be place at from each edge of the door.
Solution:
Let the distance of bar from each edge of the door be 'x'.
So as we placed the towel bar in the center of the door it divides into two i.e. '2x'
Now we can say that;

Now we will take LCM to make the denominators common we get;

Now denominators are common so we will solve the numerators.

Or 
Hence The towel bar should be placed at a distance of
from each edge of the door.