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3 years ago

14

One week, Katie Hopper earned the following commissions: Monday, $124; Tuesday, $88; Wednesday, $62; Thursday, $137; Friday, $19

5. Find her total amount of commissions for the week

2 answers:

seraphim [82]3 years ago

8 0

add them together:

124 + 88 + 62 +137 +195 = $606 total

Verdich [7]3 years ago

6 0

195+137+124+88+62=$606
This is the answer⬆️

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It’s only one question plz help (DON’T GUESS NO LINKS) please I will do anything there is a part two I’m struggling and this is

pshichka [43]

Answer:

For question 1 it's B

For question 2 it's C

Step-by-step explanation:

<u>For question 1, you have to apply the "Triangle Inequality Theorem"</u>

A+B > C

B+C > A

A+C > B

Let's say that A=22, B=17, C= 14

22+17 > 14 True

17+14 > 22 True

22+14 > 17 True

Therefore, the answer is B

<u>For question 2, you apply the rule of the sum of the triangles which is 180°</u>

70+70+? = 180

140+? = 180

? = 40

Therefore, it's C

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2 years ago

Find the missing length. The triangles are similar.

Marina CMI [18]

Answer:

RK= 13 SK= 12

Step-by-step explanation

First, we find the missing length of RK using the given information: 65-52=13

Then we divide 65 by 13 to get a scale factor: 65/13=5

(To check, we multipuly: 13*5=65)

We then apply the scale factor to MK to find SK: 60/5=12

(To check we multipuly: 5*12=60)

We now have our answers: RK:13, SK:12

4 0

3 years ago

Give the domain, range, intercepts, asymptotes, intervals of increasing and decreasing, intervals of positive and negative, symm

klemol [59]

$y = \frac{3}{x^{2} - 4} + 1$

Domain: x² - 4 ≠ 0
+ 4 + 4
x² ≠ 4
√x² ≠ √4
x ≠ ±2
x ≠ -2 and x ≠ 2
(-∞, -2) ∨ (-2, 2) ∨ (2, ∞)

Range: y ≠ 1
(-∞, 1) ∨ (1, ∞)

Intervals: Increasing: (0.25 , ∞)
Decreasing: (-∞, 0.25)

Symmetry: X-axis: Not Symmetric
Y-axis: Not Symmetric
Origin: Not Symmteric

Extrema: Maximum Relative: x = 0
Minimum Relative: Nothing

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2 years ago

11r+7s what is the answer please help!

Tasya [4]

That is the answer. you can't simplify it.

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3 years ago

Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In 2x - In(3x - 1) = 0

LenKa [72]

Answer:

$\frac{-1}{3x^2-x}$

Step-by-step explanation:

If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

<u>using these information</u>:

g(x)=ln2x then g'(x)= $\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}$

h(x)=In(3x - 1) then h'(x)= $\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}$

7 0

3 years ago