Answer:
- boat: 6 mph
- current: 2 mph
Step-by-step explanation:
The relationship between time, speed, and distance is ...
speed = distance/time
For boat speed b and current speed c, the speed downstream is ...
b +c = (16 mi)/(2 h) = 8 mi/h
The speed upstream is ...
b -c = (16 mi)/(4 h) = 4 mi/h
Adding the two equations eliminates the c term:
2b = 12 mi/h
b = 6 mi/h . . . . . divide by 2
Solving the second equation for c, we get ...
c = b -4 mi/h = 6 mi/h -4 mi/h = 2 mi/h
The speed of the boat in still water is 6 mi/h; the current is 2 mi/h.
Answer:
False
Step-by-step explanation:
At sea level, elevation is 0. This means that we can portray sea level as being the midpoint of distances below sea level and distances above sea level.
Thus, a distance of 1 m below sea level = - 1 is equivalent to a distance of 1 m above sea level albeit in opposite directions.
Hence, an elevation of 15m above sea level is greater in distance Than an elevation of - 10 m below sea level because the absolute value of 15 is greater than the absolute value of 10.
|15 - 0|= 15
|-10 - 0| = 10
Hence, elevation of - 10 below Sea level is closer to sea level than elevation of 15 above sea level
