The answer is definitely -4 1/8
Q in (-oo:+oo)
2/3 = (1/3)*q // - (1/3)*q
2/3-((1/3)*q) = 0
ddddddddd
d d
d d
(-1/3)*q+2/3 = 0 d d
d d
2/3-1/3*q = 0 // - 2/3 d d
d d
-1/3*q = -2/3 // : -1/3 d d
d d
q = -2/3/(-1/3) ddddddd dddddddd
dd dd
q = 2 dd dd
dd dddd dd
q = 2 dddddddddd dddddddddddd
Answer:
a= c/2
b= (c/2)×√3
side b is the side with the 60 degree angle.
side a is the side with the 30 degree angle.
using the theorem that the side with the 60 degree × 2 = length of side c and the side with the 60 degree × √3 = b.
I get the following equations shown above.
There’s probably an easier way to do it like with the equation to find the area of a trapezoid but i did it this way bc it’s easier for me
i split the trapezoid into a triangle and a square
with the pythagorean theorem i found the missing side length to find the area of the square (length X width)
then found the area of the triangle (base X height divided by 2)
THE ANSWER IS 68.9 CM