In arithmetic what variables look like
2 answers:
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Answer:
HT = 17 cm
<T = 58°
<H = 32°
Step-by-step explanation:
✔️Find HT:
Since it's a right triangle, we would apply the Pythagorean Theorem given as c² = a² + b²
Where,
a = HW = 15 cm
b = WT = 8 cm
c = HT
Plug in the values:
HT² = 15² + 8²
HT² = 289
HT = √289
HT = 17 cm
✔️Find <T by applying trigonometric ratio formula:
Recall: SOH CAH TOA
Reference angle (θ) = <T
HW = 15 cm = Opposite side length
WT = 8 cm = Adjacent side length
Apply CAH:
Cos θ = Adj/Hyp
Substitute
Cos T = 8/15
T =
T ≈ 58°
✔️Find <H:
Sun of interior angles of a triangle = 180°
Therefore,
m<H + m<T + m<W = 180°
Substitute
m<H + 58° + 90° = 180°
m<H + 148° = 180°
m<H = 180° - 148°
m<H = 32°
9514 1404 393
Answer:
40.5 ft
Step-by-step explanation:
Solve for the time at which the balls meet, then find the corresponding height.
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The balls will meet at the height such that the two values of h are the same.
-16t^2 +56t = h = -16t^2 +156t -248
0 = 100t -248
t = 2.48
Using the first equation to find h, we have ...
h = t(-16t +56) = 2.48(-16·2.48 +56) = 40.4736
The balls meet at a height of about 40.5 feet.
