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3 years ago

6

How do you simplify number fractions

2 answers:

scoundrel [369]3 years ago

7 0

Answer:

divide by a common multiple.

Step-by-step explanation:

blsea [12.9K]3 years ago

3 0

For example if the fraction is 50/100, what you have to do is find a number that fits into both 50 and 100. There are a lot of numbers but you have to try and find the highest number, so in this case it would be 50. So 50/50 is 1, and 100/50 would be 2, so the answer is 1/2.

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Answer:

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Evaluate - 2/5- x + (-9/10) where x = 4/5.

zalisa [80]

Answer:

- 2 1/10

Step-by-step explanation:

-2/5 -x -9/10

Let x = 4/5

-2/5 - 4/5 - 9/10

Combine like terms

-6/5 - 9/10

Get a common denominator of 10

-6/5 * 2/2 - 9/10

-12/10 - 9/10

-21/ 10

Change this to a mixed number

10 goes into 21 2 times with 1 left over

-2 1/10

6 0

3 years ago

Read 2 more answers

What is the LCD for the fractions 5/6 and 3/8 PLZ HURRY

stealth61 [152]

The least common denominator for the fractions 5/6 and 3/8 is 24. 6 x 4 = 24, 8 x 3 = 24.

6 0

3 years ago

Evaluate.<br> 1/2 (11)(15 + 17) =

Andrei [34K]

Answer: 176

Step-by-step explanation:

To evaluate the equation we have to remove the parentheses and add 15 + 17...

1/2 (11)(15 + 17) =

= 11 * 32 * 1/2

Now, we have to turn it into a fraction and multiply it...

$\frac{1*11*32 }{2}$

= $\frac{352}{2}$

352 ÷ 2 = 176

I hope this helps!

8 0

3 years ago

Read 2 more answers

What is the value of log 43? Use the calculator. Round your answer to the nearest tenth.

Bad White [126]

Answer:

The value of log 43is 1.633

Step-by-step explanation:

Explanation:

Suppose you know that:

$\begin{array}{l}{\log 2 \approx 0.30103} \\{\log 3 \approx 0.47712}\end{array}$

Then note that:

$43=\frac{129}{3} \approx \frac{128}{3}=\frac{2^{7}}{3}$

So

$\log 43 \approx \log \left(\frac{2^{7}}{3}\right)=7 \log 2-\log 3 \approx 7 \cdot 0.30103-0.47712=1.63009$

We know that the error is approximately:

$\log \left(\frac{129}{128}\right)=\log 1.0078125=\frac{\ln 1.0078125}{\ln 10} \approx 0.00782 .3=0.0034$

So we can confidently give the approximation:

$\log 43 \approx 1.633$

6 0

3 years ago