1)
-30x^5+36x^4-42x^3
2)(9b+9)^2 by ( a+b)^2=a^2+b^2+2ab
49b^2+49+162b
Answer:
6-4x
Step-by-step explanation:
Answer: 48 sweets
Step-by-step explanation:
Let the total number of sweets be X
Thereforee, 5X/11 + 6X/11 = X.
When Sarah ate 16 sweets, the ratio of sweets left is 1 : 2.
[(5X/11) - 16] / [6X/11] = 1/2.
Cross multiply,
10X/11 - 32 = 6X/11
10X/11 - 6X/11 = 32
4X/11 = 32
4X = 32 × 11
4X = 352
X = 352/4
X = 88
therefore, sarah = 5X/11
= (5 × 88) ÷ 11 = 440/11 = 40
Henry = 6X/11
= (6 × 88) ÷ 11
= 48
Therefore, the original ratio was:
5 : 6 = 40 : 48
Sarah ate 16 sweets, her balance is:
40 – 16 = 24
Sarah : Henry = 24:48 = 1:2
Henry has 48 sweets.
Answer:
41
Step-by-step explanation:
First, we need to find the sum of the ages of the first five people.
20 + 15 + 25 + 17 + 20 = 97
Then, multiply 23 by 6 to get the sum of the ages of all six people.
23 x 6 = 138
We then subtract 97 from 138 to get the age of the sixth person.
138 - 97 = 41