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Ainat [17]
3 years ago
8

200 years ago, as it became more and more evident that the

Mathematics
1 answer:
svp [43]3 years ago
5 0

Answer:

The American population was 20% of the British population.

Step-by-step explanation:

Let us call A the american population, B the British population before the migration, and x the population that migrated from America to Britannia.

Now, the population x that migrated was 20% of the american population:

(1).\: \: x = 0.2A,

and the same population x increase the British population by 4%:

x+B = 1.04B \\\\ (2). \:\:x = 0.04B.

Combining equation (1) and (2) we get:

0.2A = 0.04B

A = \dfrac{0.04B}{0.2}

\boxed{A = 0.2B}

Thus, the American population was 20% of the British population.

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Let h(x) be a function whose second derivative is h 00(x) = x 3 − 4x 2 + 5x. h(x) has critical points at x = −1, x = 0, and x =
leva [86]

Answer:

*The function has a minimum in x=-1

*The function has a maximum in x=1

*The second derivative is not enough to determine if the function has either a maximum or a minimum in x=0.

Step-by-step explanation:

1. Evaluate the second derivative in the first critical point x=-1:

h"(x)=x^{3}-4x^{2}+5x

h"(-1)=(-1)^{3}-4(-1^{2})+5(-1)

h"(-1)=-1-4-5

h"(-1)=-10

As the value is smaller than zero, the function has a minimum in x=-1

2. Evaluate the second derivative in the second critical point x=1

h"(x)=x^{3}-4x^{2}+5x

h"(1)=(1)^{3}-4(1^{2})+5(1)

h"(1)=1-4+5

h"(1)=2

As the value is larger than zero, the function has a maximum in x=1

3. Evaluate the second derivative in the third critical point x=0

h"(x)=x^{3}-4x^{2}+5x

h"(0)=(0)^{3}-4(0^{2})+5(0)

h"(0)=0-0+0

h"(0)=0

As the value is equal to zero, the second derivative is not enough to determine if the function has either a maximum or a minimum in x=0.

6 0
3 years ago
Can someone please help me with this?
gladu [14]
Okay first you need to do ×+1___×-3 then
5 0
3 years ago
In one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the enti
jekas [21]

Answer:

X \sim Hyp (N = 810, M=102, n=4)

P(X=0) = \frac{(102C0)(810-102 C 4-0)}{810C4}  

And solving we got:

P(X=0)= \frac{(102C0) (708C4)}{810C4} = 0.583

So then for the problem given the probability that the entire bath will be accepted (none is defective among the 4) is 0.583

Step-by-step explanation:

For this case we can model the variable of interest with the hypergeometric distribution. And with the info given we can do this:

X \sim Hyp (N = 810, M=102, n=4)

P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}  

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes  

And for this case we want to find the probability that none of the scales selected would be defective so we want to find this:

P(X=0)

And using the probability mass function we got:

P(X=0) = \frac{(102C0)(810-102 C 4-0)}{810C4}  

And solving we got:

P(X=0)= \frac{(102C0) (708C4)}{810C4} = 0.583

So then for the problem given the probability that the entire bath will be accepted (none is defective among the 4) is 0.583

6 0
3 years ago
AT&T offers a deal for internet service that is $20 a month. There is an intial fee of $50. If Tim spent $330 on his interne
GenaCL600 [577]

Answer:

162 months

Step-by-step explanation:

if I'm correct it should be 162

3 0
2 years ago
Leslie is a biologist. She is going to randomly select one animal from her lab to study. There are 5 salamanders, 3 crayfish, an
denpristay [2]
She'll most likely pick a minnow
8 0
3 years ago
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