it should be 8
to find median you line up the numbers in order and divide by 2
Answer:
"The range of the function is all real numbers less than or equal to 9."
Step-by-step explanation:
For this question the domain is (-∞,∞)
The range is all numbers less than 9 (the y-coordinate of the vertex)
The reason the numbers are less than 9 is because the graph is concave down (aka it looks like a frowny face)
Therefore the answer is "The range of the function is all real numbers less than or equal to 9."
Answer:
Step-by-step explanation:
Remark.
I take it we are only concerned with the deep lime face that we can see closest to us.
Construction
Draw one line that goes from the right of the left foot up to the 18 foot line
Draw another line that goes from the left of the right foot up to the 18 foot line.
label the width of the right foot as 18 - 6 - 6 = 6
Solution
Right foot
Area = L * w
L = 12 feet
w = 6 feet
Area = 12*6 = 72
Left foot (same area) 72
Area above the door.
Height = 12 - 6 = 6
width 6
Area = 6 * 6 = 36
Answer: Total Area = 72 + 72 + 36 = 180
Answer:
The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Step-by-step explanation:
The area for a rectangle is given by the formula:
Where <em>w</em> is the width and <em>l</em> is the length.
We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.
First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>
![\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BdA%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bw%5Cell%5D)
By the Product Rule:
Since we know that dl/dt = 6 and that dw/dt = 5:
We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:
The area of the rectangle is increasing at a rate of 84 square centimeters per second.
<span>#include <iostream>
using namespace std;
class InventoryTag {
public:
InventoryTag();
int getQuantityRemaining() const;
void addInventory(int numItems);
private:
int quantityRemaining;
};
InventoryTag::InventoryTag() {
quantityRemaining = 0;
}
int InventoryTag::getQuantityRemaining() const {
return quantityRemaining;
}
void InventoryTag::addInventory(int numItems) {
if (numItems > 10) {
quantityRemaining = quantityRemaining + numItems;
}
}
int main() {
InventoryTag redSweater;
int sweaterShipment = 0;
int sweaterInventoryBefore = 0;
sweaterInventoryBefore = redSweater.getQuantityRemaining();
sweaterShipment = 25;
cout << "Beginning tests." << endl;
// FIXME add unit test for addInventory
/* Your solution goes here */
cout << "Tests complete." << endl;
return 0;
}</span>
