Which of the following ordered pairs is represented by a point located on the y-axis?

Mathematics

1 answer:

MatroZZZ [7]3 years ago

4 0

The last one (0, -3) because it doesn’t move to the left/right, only up/ down.

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B%20-%204%7D%20%20%2B%2011%20%3D%205" id="TexFormula1" title=" \frac{x}{ -

snow_lady [41]

Our equation is:

(x/-4)+11=5; we need to get x by itself in order to solve. Let's subtract 11 from both sides. (x/-4)=-6; let's now multiply both sides by -4. x=24; let's check to see if x is 24 by plugging it in.

24/-4=-6+11=5

So, x=24.

4 0

3 years ago

A pair of shoes costs three times as much as a scarf. The total cost of 1 pair of shoes and 1 scarf is $32. If s represents the

san4es73 [151]

3s+s=32

I did it on TTM and it was correct ^^

6 0

4 years ago

Which expression is a fourth root of -1+isqrt3?

aleksklad [387]

Answer:

Step-by-step explanation:

$\sf n^{th}$ roots of a complex number is given by DeMoivre's formula.

$\sf \boxed{\bf r^{\frac{1}{n}}\left[Cos \dfrac{\theta + 2\pi k}{n}+i \ Sin \ \dfrac{\theta+2\pi k}{n}\right]}$

Here, k lies between 0 and (n -1) ; n is the exponent.

$\sf -1 + i\sqrt{3}$

a = -1 and b = √3

$\sf \boxed{r=\sqrt{a^2+b^2}} \ and \ \boxed{\theta = Tan^{-1} \ \dfrac{b}{a}}$

$\sf r = \sqrt{(-1)^2 + 3^2}\\\\ = \sqrt{1+9}\\\\=\sqrt{10}$

$\sf \theta = tan^{-1} \ \dfrac{\sqrt{3}}{-1}\\\\ = tan^{-1} \ (-\sqrt{3})$

$\sf = \dfrac{-\pi }{3}$

n = 4

For k = 0,

$\sf z = \sqrt[4]{10}\left[Cos \ \dfrac{\dfrac{-\pi}{3} +0}{4}+iSin \ \dfrac{\dfrac{-\pi}{3}+0}{4}\right] \\\\\\z= \sqrt[4]{10} \left[Cos \ \dfrac{ -\pi }{12}+iSin \ \dfrac{-\pi}{12}\right]\\\\\\z = \sqrt[4]{10}\left[-Cos \ \dfrac{\pi}{12}-i \ Sin \ \dfrac{\pi}{12}\right]$