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ivann1987 [24]
4 years ago
12

A new park was designed to contain two circular gardens. Garden A has a diameter of 50 m, and garden B has a diameter of 70 m. T

he gardener wishes to put down weed block fabric on the two gardens before the plants are planted in the ground. How much fabric will be needed to cover the area of both gardens?
Mathematics
1 answer:
Nastasia [14]4 years ago
5 0

Answer:

5,811.95\  m^2 of fabric.

Step-by-step explanation:

-The amount of fabric needed is equivalent to the  area of the two gardens.

-We calculate the combined areas as:

A=A_s+A_b\\\\=\pi r^2+\pi R^2\\\\=\pi(25^2+35^2)\\\\=1850\pi \ m^2\\\\=5811.95\ m^2

Hence, 5811.95 sq meters of fabric will be needed to cover the area of both gardens.

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5z+2z^3+3z^4 in standard form
julia-pushkina [17]

Answer:

= 3z4 - 2z2 -5z

Step-by-step explanation:

6 0
3 years ago
An event lasts 4 hours and 20 minutes. How long did the event last in seconds?
enyata [817]
20*6=120seconds +3600second in an hour so 3600*4=14400

1210+14400=14520

14520 is the answer I hope this helps!


8 0
3 years ago
Read 2 more answers
Sales at an airport shop has increased by 25 transactions to a total of 400 transactions per day. What is the increased transact
Zielflug [23.3K]

Answer:

6.66

Step-by-step explanation:

3 0
3 years ago
Jacob transformed quadrilateral FGHJ to F'G'H'J'.
Rudik [331]

Answer:

A. Reflection across the line x = 1

Step-by-step explanation:  

Please find the attachment.

We have been given that Jacob transformed quadrilateral FGHJ to F'G'H'J'.  We are asked to find which transformation Jacob used to reflect FGHJ to F'G'H'J'.

Since we know that while reflecting a figure, the line of reflection will lie between the original figure and reflected figure. Each point of the reflected figure will have the same distance from the line of reflection as the corresponding point of the original figure.              

Now let us see our given choices one by one.

A. Reflection across the line x = 1.

Upon looking at point G and G' we can see that both points are equidistant (2 units) from the line x=1. Other corresponding points of both quadrilaterals are also equidistant from line x=1, therefore, Jacob used the reflection across the line x=1 to transform quadrilateral FGHJ to F'G'H'J'.

B. Reflection across the line y = 1 .      

If Jacob had reflected quadrilateral across line y=1, the points of quadrilateral F'G'H'J' will lie in second and third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option B is not a correct choice.

C. Reflection across the line y-axis.

If Jacob had reflected quadrilateral across y-axis, the coordinates of points of quadrilateral F'G'H'J' will be G'(1,4), H'(1,2), J'(4,0) and F'(2,5). Therefore, option B is not a correct choice.

D.  Reflection across the x -axis.

If Jacob had reflected quadrilateral across x-axis, the points of quadrilateral F'G'H'J' will lie in third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option D is not a correct choice.

3 0
3 years ago
3. Jim bought a new pair of glasses. The lenses had six sides. The lenses were in the shape of a A. hexagon. B. heptagon. C. qua
Vladimir [108]
Best Answer:<span>  </span><span>6 sides is a hexagon. 

the spoke of a wheel is like a radius. Circumference is equal to 2πr so r = 42/2π ≈ 6.69 inches, ans. D. 

that's it! ;)</span>
5 0
3 years ago
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