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Usimov [2.4K]
3 years ago
12

Find the length of the arc on a circle with the radius of 2.4 km and is intercepted by a central angle measuring 150°. Leave you

r answer in terms of pi
Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0

Formula to find the arc length is:

s=\frac{\theta}{360} 2\pi r

Where, s= arc length,

r = radius of the circle

\theta = central angle in degrees.

According to the given problem, \theta= 150 and r =2.4.

So, first step is to plug in these values in the above formula to get the arc length.

s=\frac{150}{360} *2\pi *2.4

=\frac{5}{12} *2\pi *2.4

=0.41667*2\pi *2.4

=2\pi

So, arc length is 2\pi.

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Answer:

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Step-by-step explanation:

Larger number = x

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Multiply 2(y + 6)

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3 0
3 years ago
Show that triangle MPT =Triangle MTP​
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Unusual notation.  I won't fuss with it.

a. We have isosceles PRT, so angle  RPT = angle RTP.

By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.

We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP

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That's the first part.

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PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees

Bad drawing, PUT looks acute.

angle PRT = 68 degrees, angle PUT = 96 degrees

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